M. Crespo et al. / Polyhedron 21 (2002) 105–113
111
Compound
[PtMe(3,4,5-C6HF3CHꢀNCH2C6H5)-
8.52 [s, He]. 19F NMR (CDCl3): l= −109.17 [dd,
J(Pt–F5)=390, J(F5–F4)=30, J(P–F5)=16, F5];
−144.31 [m, F3]; −161.64 [m, F4]. 31P NMR (acetone-
d6): l=46.37 [s, J(Pt–PA)=1718, PA]; 47.27 [dd,
J(Pt–PB)=2274, J(PB–F5)=16, J(PB–F4)=8, PB].
\M=2.3 V−1 cm2 mol−1 (10−3 M in acetone). Anal.
Found: C, 53.9; H, 4.7; N, 3.2. Calc. for
C38H39F3N2P2Pt: C, 54.48; H, 4.69; N, 3.34%.
PPh3] (3) was obtained from the reaction of 50 mg
(9.6×10−5 mol) of compound 1 with the equimolecu-
lar amount (25 mg) of PPh3 in acetone (20 ml). After
continuous stirring during 2 h, the solvent was removed
in a rotary evaporator and the resulting yellow solid
was washed with hexane (2×5 ml), and diethylether
(2×5 ml) and dried under vacuum. Yield 55 mg (80%).
1H NMR (acetone-d6): l=0.97 [dd, 2J(Pt–H)=83,
Compound [PtMe2I(3,4,5-C6HF3CHꢀNCH2C6H5)-
(SMe2)] (4a/4b) was obtained from 20 mg of compound
1 (3.84×10−5 mol) and 10 mL of methyl iodide in 0.7
ml of CDCl3 in a 5 mm NMR tube and was character-
3J(P–H)=9, J(F–H)=6, Mea]; 4.22 [s, J(Pt–H)=8,
3
Hd]; {6.79 [m, 1H]; 7.40 [m], 7.64 [m], aromatics}; 8.63
[s, 3J(Pt–He)=55, He]. 19F NMR (acetone-d6): l=
−122.62 [m, J(Pt–F5)=87, J(F5–F4)=24, J(P–F5)=
J(F5–F3)=J(F5–H)=7, F5]; −146.01 [m, F3];
−159.80 [m, F4]. 31P NMR (acetone-d6): l=29.79 [dd,
J(Pt–P)=2631, J(P–F5)=10, J(P–F4)=7]. Anal.
Found: C, 54.7; H, 3.8; N, 2.0. Calc. for
C33H27F3NPPt: C, 55.00; H, 3.78; N, 1.94%.
1
ised by NMR spectra. H NMR (CDCl3): l={0.81 [s,
2
2J(Pt–H)=68], 1.46 [s, J(Pt–H)=70], Mea}; {1.72 [d,
2J(Pt–H)=68, J(F–H)=6], 2.10 [d, 2J(Pt–H)=68,
J(F–H)=7], Meb}; 2.21 [s, 3J(Pt–H)=15, Mec]; 5.25–
3
3
5-50 [m, Hd]; {8.12 [s, J(Pt–H)=47], 8.30 [s, J(Pt–
H)=42], He}.
Compound
[{PtMe2I(3,4,5-C6HF3CHꢀNCH2C6-
Compound
[PtMe(3,4,5-C6HF3CHꢀNCH2C6H5)-
H5)}2] (5) was obtained as a pale yellow solid from the
reaction of an excess of methyl iodide (0.1 ml) with 50
mg (9.3×10−5 mol) of compound 2 carried out in
acetone (20 ml). The mixture was stirred for 3 h, and
the solvent was removed under vacuum. The residue
was washed with diethylether (3×5 ml) and dried
(PPh3)2] (7) was obtained as a white solid by an
analogous procedure using 100 mg (1.9×10−4 mol) of
PPh3. Yield 80 mg (85%). H NMR (acetone-d6): l=
1
2
3
3
0.27 [dd, J(Pt–H)=65, J(PA–H)=8, J(PB–H)=7,
Mea]; {4.74 [d], 4.87 [d], J(H–H)=13, AB pattern,
Hd}; 7.13–7.24 [m, aromatics]; 9.40 [s, He]. 19F NMR
(acetone-d6): l= −113.96 [ddd, J(Pt–F5)=412,
J(F5–F4)=30, J(P–F5)=15, J(F5–F3)=3, F5];
−148.54 [m, F3]; −164.33 [ddt, J(F5–F4)=30, J(F4–
F3)=19, J(P–F4)=J(F4–H)=7, F4]. 31P NMR (ace-
1
under vacuum. Yield 35 mg (63%). H NMR (CDCl3):
2
2
l=1.27 [s, J(Pt–H)=75, Mea]; 2.94 [d, J(Pt–H)=
69, J(F–H)=8, Meb]; {5.63 [d], 5.92 [d], J(H–H)=16,
AB pattern, Hd}; {7.01 [m, 1H]; 7.37–7.57 [m, 5H],
aromatics}; 8.05 [s, 3J(Pt–Hd)=45, He]. 19F NMR
(CDCl3): l= −127.90 [dt, J(F5–F4)=21, J(F5–F3)=
J(F5–H)=8, F5]; −142.59 [m, F3]; −153.64 [td,
J(F4–F3)=J(F4–F5)=20, J(F4–H)=7, F4]. 195Pt
NMR (CDCl3): −2700 [s]. FAB(+) MS (NBA, m/z):
1200 ([M]+); 1073 ([M−I]+); 1043 ([M−I–2Me]+);
1028 ([M−I−3Me]+); 779 ([M−I−3Me−L]+).
Anal. Found: C, 31.8; H, 2.5; N, 2.3. Calc. for
C32H30F6I2N2Pt2: C, 32.01; H, 2.52; N, 2.33%.
tone-d6):
l=25.38
[d,
J(Pt–PA)=1908,
J(PA–PB)=15, PA]; 26.01 [td, J(Pt–PA)=2311, J(PB–
PA)=J(PB–F5)=15, J(PB–F4)=8, PB]. Anal. Found:
C, 61.9; H, 4.3; N, 1.4. Calc. for C51H42F3NP2Pt: C,
62.32; H, 4.31; N, 1.44%.
Compound
[PtMe(3,4,5-C6HF3CHꢀNCH2C6H5)-
(dppe)] (8) was obtained as a white solid by an
analogous procedure using 38 mg (9.5×10−5 mol) of
dppe. Yield 70 mg (85%). H NMR (acetone-d6): l=
1
Compound [PtMe2I(3,4,5-C6HF3CHꢀNCH2C6H5)-
(PPh3)] (6) was obtained as a white solid by an
analogous procedure from 50 mg (6.9×10−5 mol) of
0.48 [t, 2J(Pt–H)=67, 3J(PA–H)=3J(PB–H)=6,
Mea]; 2.44 [m, Hf,g]; 4.36 [s, Hd]; {7.12–7.32 [m], 7.45–
7.55 [m], 7.70–7.79 [m], 7.89–7.98 [m], aromatics}; 8.65
[s, He]. 19F NMR (CDCl3): l= −114.20 [dd, J(Pt–
F5)=385, J(F5–F4)=27, J(P–F5)=11, F5]; −147.38
[m, F3]; −163.92 [ddt, J(F5–F4)=29, J(F4–F3)=20,
J(P–F4)=J(F4–H)=8, F4]. 31P NMR (acetone-d6):
l=46.58 [s, J(Pt–PA)=1718, PA]; 47.36 [m, J(Pt–
PB)=2287, PB]. Anal. Found: C, 57.4; H, 4.4; N, 1.6.
Calc. for C41H36F3NP2Pt: C, 57.48; H, 4.24; N, 1.63%.
1
compound 3. Yield 50 mg (83%). H NMR (CDCl3):
2
3
l=1.38 [d, J(Pt–H)=60, J(P–H)=8, Mea]; 2.20 [t,
2J(Pt–H)=69, 3J(P–H)=J(F–H)=8, Meb]; {4.58 [d],
5.52 [d], J(H–H)=17, AB pattern, Hd}; {6.86 [m, 4H];
7.31–7.58 [m], 7.64 [m], aromatics}; 7.69 [s, 3J(Pt–
Hd)=44, He]. 19F NMR (CDCl3): l= −127.35 [dt,
J(F5–F4)=21, J(F5–F3)=J(F5–H)=7, F5]; −144.57
[m, F3]; −153.62 [td, J(F4–F3)=J(F4–F5)=21, J(F4–
H)=6, F4]. 31P NMR (CDCl3): l= −11.32 [s, J(Pt–
P)=1001]. Anal. Found: C, 47.2; H, 3.5; N, 1.6. Calc.
for C34H30F3INPPt: C, 47.34; H, 3.51; N, 1.62%.
Compound
[PtMe(3,4,5-C6HF3CHꢀNCH2CH2-
NMe2)(dppe)] (9) was obtained as a white solid by an
analogous procedure from 50 mg (1.14×10−4 mol) of
the compound [PtMe(3,4,5-C6HF3CHꢀNCH2CH2-
Compound
[PtMe(3,4,5-C6HF3CHꢀNCH2CH2-
1
NMe2)] and 45 mg of dppe. Yield 80 mg (84%). H
NMe3)(dppe)]I (10) was obtained as a yellow solid from
the reaction of an excess of methyl iodide (0.1 ml) with
35 mg (4.18×10−5 mol) of compound 9 carried out in
acetone. The mixture was stirred for 3 h, and the
NMR (acetone-d6): l=0.46 [t, J(Pt–H)=68, J(PA–
H)=3J(PB–H)=7, Mea]; 2.15 [s, Meg]; {2.20–2.45 [m],
3.26 [t, J(H–H)= 7, Hd,f,h,i} 7.14–7.76 [m, aromatics];
2
3