G. Cavinato et al. / Journal of Molecular Catalysis A: Chemical 219 (2004) 233–240
239
Table 3
hydride is trapped by ethene, for example via reaction with
the acid [33,34]. As a matter of fact, when complex (I) is
used in high concentration and in the presence of an excess
of TsOH, at 80 ◦C under 4.0 MPa of CO/C2H4 = 1/1, a TOF
of 380 h−1 is obtained and it is recovered as complex (III)
(98%) (Table 2, entry 4).
Another intermediate consuming side reaction can be the
reaction of a Pd(II)–CH2CH3 intermediate with the acid that
gives ethane and a complex of type (III). As a matter of
fact, ethane has been detected by GC during the course of
catalysis.
As already mentioned, an excess of acid may consume
the active Pd(II)–H species with evolution of H2, but on
the other hand it may stabilize the hydrides preventing their
deprotonation to inactive Pd(0) species or reoxydise them
back to Pd(II)–H species. As matter of fact, also the inactive
Pd(0) complexes (IV), (V) and (VI) catalyze efficiently the
HMC of ethene if an excess of TsOH is used (Table 3, entries
11–13).
Catalytic activity of Pd(II) and Pd(0) complexes
Entry no.
Complex
TsOH/Pd
(mol/mol)
PPh3/Pd
(mol/mol)
TOF
(h−1
Pdmet
)
1
2
3
4
5
6
7
8
9∗
10∗
11
12
13
(I)
(I)
(I)
(I)
(II)
(II)
(III)
(III)
(I)
(III)
(IV)
(V)
(VI)
–
10
–
10
10
–
10
–
1
–
–
8
8
8
–
8
–
8
8
–
8
30
45
40
420
420
Traces
410
Traces
210
220
410
400
Yes
Yes
No
No
No
Yes
No
Yes
No
No
Yes
No
No
1
10
10
10
330
Run conditions: catalyst precursor: 0.1 mmol; MeOH: 50 ml; H2O:
800 ppm; T: 353 K; P: 4.5 MPa (CO/C2H4 = 1/1); reaction time: 2 h; stir-
rer speed: 700 rpm; (VI) = [Pd(PPh3)4]. *MeOH = 40 ml; cyclohexene
= 10 ml; P = 2.0 MPa (CO).
In conclusion, the results presented in this paper give fur-
ther support to the suggestion that catalysis occurs via an
initial Pd(II)–H species. In addition they suggest that H2O
promotes the catalysis, even when complex (I) is used as pre-
cursor, by converting species of type (II) and (III), that are
likely to form during the catalysis, to Pd–(COOH) species
and hence to active Pd(II)–H species.
absence of TsOH and PPh3, complex (I) leads, during 2 h,
to a TOF of 30 h−1 (entry 1). This value is only indicative
since under these conditions the complex decomposes to
palladium metal. By adding an excess of TsOH only a slight
increase of TOF is observed (45 h−1, entry 2). Also in this
case decomposition to palladium metal occurs. Practically,
the same result is obtained when PPh3 is added (without
TsOH), but the formation of Pd metal is avoided (entry 3).
(420 h−1, entry 4), practically the same as that achieved
when using complex (II) or (III) under the same conditions.
However, these complexes in the absence of TsOH and PPh3
are inactive (entries 5–8) [27,29].
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