Synthesis of (Z)-Heneicosa-6-en-11-one To synthesize (Z)-heneicosa-6-en-11-one, you'll need a suitable alkene precursor. Start with an alkene compound, preferably with the desired chain length, and a double bond at the 6th position. Carry out a Wittig reaction, or a similar method, to convert the alkene into the corresponding alkene with the desired chain length. Ensure that the double bond is in the Z configuration. Oxidize the terminal alkene (the 11th position) to obtain the ketone.
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2-hexyl-3-methylcyclohex-2-enone
2
Potassium
glyoxamide
3,5-Pyridinedicarbonitrile, 6-amino-1-(2,3-dihydro-1,5-dimethyl-3-oxo-2-phenyl-1H-pyrazol-4-yl)-1, 2-dihydro-4-(4-methoxyphenyl)-2-oxo-
Piperidine
PHENYL ISOTHIOCYANATE
methyl 2-(2,4-dichloro-5-fluorobenzoyl)-2-(2-piperidylidene)-acetate
3,5-Pyridinedicarbonitrile, 6-amino-1-(2,3-dihydro-1,5-dimethyl-3-oxo-2-phenyl-1H-pyrazol-4-yl)-1, 2-dihydro-4-(4-methoxyphenyl)-2-oxo-
Piperidine
PHENYL ISOTHIOCYANATE
3,5-Pyridinedicarbonitrile, 6-amino-1-(2,3-dihydro-1,5-dimethyl-3-oxo-2-phenyl-1H-pyrazol-4-yl)-1, 2-dihydro-4-(4-methoxyphenyl)-2-oxo-
Piperidine
PHENYL ISOTHIOCYANATE
