
Inorganic Chemistry p. 1296 - 1305 (1987)
Update date:2022-08-03
Topics:
McKenna, Stephen T.
Muetterties, Earl L.
The reaction of the coordinatively unsaturated binuclear complex (μ-H)2Rh2[P(O-i-Pr)3]4 with 1 equiv of an isocyanide RNC yields the monoadduct (μ-H)2(RNC)Rh2[P(O-i-Pr)3]4. These complexes adopt an unsymmetrical structure with one trigonalbipyramidal and one square-pyramidal rhodium center. In the case of the relatively compact isocyanides with R = 4-ClC6H4, PhCH2, and n-Bu, the isocyanide symmetrically bridges the two rhodium centers, while for larger isocyanides such as t-BuNC, steric interactions force the isocyanide into a position in which it is strongly associated with the trigonal-bipyramidal Rh and only weakly bonded to the other Rh. For all the monoadducts, a rapid fluxional process exchanges the Rh and P environments and generates a symmetrical time-averaged structure at room temperature. Variable-temperature 31P{1H} NMR spectroscopy was used to obtain the activation parameters for this process; the value of ΔH? ranges from 9.7 to less than 7.7 kcal/mol, while ΔS? is nearly zero. Treatment of (μ-H)2(RNC)Rh2[P(O-i-Pr)3]4 with additional RNC results in a complex fragmentation reaction, with the product distribution dependent upon the nature of the isocyanide. In addition to mononuclear fragmentation products, the zerovalent binuclear compound (μ-RNC)2Rh2[P(O-i-Pr)3]4 is formed, particularly in the case of R = 4-ClC6H4. The compound (μ-4-ClC6H4NC)2Rh2[P(O-i-Pr) 3]4 crystallizes in the monoclinic space group C2/c with a = 15.526 (2) A, b = 20.351 (4) A, c = 20.975 (3) A, β = 94.34 (1)°, and Z = 4. Its X-ray crystal structure (R = 0.030, Rw = 0.038 for 3045 data with I > 3σ) shows a nonplanar geometry at each Rh atom with a bent pair of bridges (dihedral angle of 135.8° between the Rh2C planes) and a Rh-Rh separation of 2.640 (1) A. The chemistry of the isocyanide compounds is compared and contrasted with that of their CO analogue.
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