122
D. Kruber et al. / Journal of Organometallic Chemistry 572 (1999) 117–123
dation state from Rh(I) to Rh(III) [18]. The 119Sn
satellite signals in the 31P-NMR spectrum represent
the AB part of the ABLX and the ABMX spin sys-
tems mentioned above. At the present stage of our
studies an assignment of the 31P-NMR signals is not
possible.
3. Experimental
All manipulations were performed under dry argon.
Elemental analyses were carried out at the Microana-
lytical Laboratory of the Chemical Department. In-
frared spectra were measured on a Specord 75 IR
(CsBr). The NMR spectra were recorded on Gemini
200 (Varian) or Unity 500 (Varian) spectrometers. Sol-
vent signals (1H, 13C), Me4Sn (119Sn) and 85% H3PO4
(31P) were used as references. The NMR spectra simu-
lations were performed with the program PERCH
[21]. The molecular weight determination of 1 was
performed in benzene at 45°C (concentration=0.01
mol l−1) using a Knauer osmometer.
The 119Sn-NMR spectrum exhibits a multiplet at
249.7 ppm and a virtual triplet at 319.4 ppm. Both
signals are doubled by Sn–Rh coupling. The assign-
ment of the two 119Sn-NMR signals is based on the
different trans influence of the CO and the Cl ligand.
With respect to the higher trans influence of CO (see
1
Section 2.2) the J(119Sn(2)103Rh) coupling constant of
1
221.9 Hz is 110 Hz smaller than the J(119Sn(1)103Rh)
coupling. Therefore, the high-field 119Sn-NMR signal
at 249.7 ppm can be assigned to the Sn(2) atom and
the signal at 319.4 ppm to the Sn(1) atom. The low-
field position of the latter signal is also in agreement
with the high electronegativity of the Cl atom in the
trans position. Each 119Sn nucleus couples with both
phosphorus nuclei, but, in a different way. The
2J(119SnRh31P) is the one coupling the other one
nJ(119Sn, 31P) represents the sum of the two contribu-
3.1. [{Me2(Cl)SnCH2CH2PPh2}2Rh(CO)Cl] (1)
Solutions of [Rh(CO)2Cl]2 (300 mg, 0.77 mmol) and
Me2(Cl)SnCH2CH2PPh2 [3] (613 mg, 1.54 mmol) in
benzene (in each case 10 ml) are dropped simulta-
neously in pure benzene (50 ml) and the mixture is
stirred for 2 h to give a light yellow solution. During
the reaction the equivalent amount of CO (35 ml) is
released. After evaporation of the solvent the residue
is washed with pentane and dried in vacuo. 1 is ob-
tained as a yellow fine-crystalline compound (1.4 g,
96%); m.p. 124–126°C.
2
3
tions ꢀ J(119SnRh31P)ꢀ and ꢀ J(119SnCC31P)ꢀ within the
chelate ring. The coupling constants are determined by
computer simulation using the 119Sn-NMR spectrum
and the satellite part of the 31P-NMR spectrum. As
C33H40Cl3OP2RhSn2 (961.3): anal. (exp./calc.) C,
n
mentioned above an assignment of the J(119Sn, 31P)
41.51/41.23; H, 4.22/4.19; IR (CsBr, cm−1): 1975
coupling constants to a certain phosphorus atom is
not possible.
1
2
(CO). H-NMR (C6H6): l 0.56 (s, 6H, SnCH3, J(H,
Sn) 60.2 Hz); 1.43 (m, 4H, SnCH2); 2.84 (m, 4H,
The significant down field shift both of the 31P and
the 119Sn-NMR signals is due to the fact that these
atoms are included in a five-membered ring (‘ring ef-
fect’ of chemical shifts [19]). We have observed the
3
PCH2, J(H, Sn) 70 Hz); 6.99–7.68 (m, 20H, PC6H5)
ppm.
¸¹¹¹¹¹¹¹¹¹º
3.2. [{Me(Cl)SnCH2CH2PPh2}2Rh(CO)Cl] (2)
same effect for the bicyclic platinum complex
¸¹¹¹¹¹¹¹º
[{Me2SnCH2CH2PPh2}2Pt] [4].
A solution of 1 (1.0 g, 1.04 mmol) in toluene (50 ml)
was heated under stirring for 2 days whereby it slowly
turned from yellow to orange. The solvent was removed
and the yellow residue recrystallized from CH2Cl2/hex-
ane giving pure 2 (560 mg, 61%); m.p. 155°C.
The values of 211 and 224 Hz, respectively, for the
nJ(H, Sn) coupling constant for two of the four PCH2-
protons in the chelate rings of 2 are remarkably high.
Our knowledge about the mechanism of the trans-
formation of 1 into 2 is only vague. Certainly, the first
step is the intramolecular oxidative addition of the
Sn–C(Me) bond of one ligand to the Rh(I) centre of
1. Efforts to detect the resulting intermediate complex
failed. The higher reactivity of a Sn–C bond com-
pared with a Sn–Cl bond in oxidative additions of
triorganotin halides also is described for the reaction
of R3SnCl with Pd0 and Pt0 complexes [20]. The in-
tramolecular rearrangement of the intermediate com-
plex to 2 by demethylation both of the Rh atom and
the tin atom of the second ligand is accompanied by
the formation of methane and ethylene in a molar
ratio of 2:1. This could be proved by gas-chromato-
graphic investigation of the reaction.
C31H34Cl3OP2RhSn2 (931.2): anal. (exp./calc.) C,
40.53/39.98; H 4.53 /3.68; Cl 11.42/12.03; IR (CsBr,
cm−1): 2047 (CO). 1H-NMR (CD2Cl2): l −0.28 (s,
2
3H, SnCH3, J(H, Sn) 56.8 Hz); 0.05 (s, 3H, SnCH3,
2J(H, Sn) 56.5 Hz); 1.46 (m, 1H, SnCH2); 1.84 (m, 2H,
SnCH2); 1.92 (m, 1H, SnCH2); 2.35 (m, 1H, PCH2);
3
2,58 (m, 1H, PCH2); 2.96 (m, 1H, PCH2, J(H, Sn) 211
3
Hz); 3.60 (m, 1H, PCH2, J(H, Sn) 224 Hz); 7.37–8.20
(m, 20H, PC6H5) ppm.
3.3. Crystallographic studies
Crystal data and details of the data collection and
refinement of 1 and 2 are summarized in Table 4.