Heteronuclear and heterovalent diphenylphosphido-bridged complexes of rhodium, iridium and ruthenium. Crystal structure of *1/2Et2O (COD = 1,5-cyclooctadiene)

Article abstract of DOI:10.1016/0022-328X(91)86254-N

Mononucelar complexes of formulae , BF4 and BF4 (M = Rh, Ir; L = C5Me5.M = Ru; L = p-Cymene; R = Ph, H; R' = H; Hacac = acetylacetone, but not in all possible combinations) have been prepared from the corresponding <2(μ-Cl)2> or and HPRR'.Complexes react with 2 (M' = Rh; diolefin = tetrafluorobenzobarrelene (TFB), 1,5-cyclooctadiene (COD).M' = Ir; diolefin = COD) to yield diphenylphoshido-bridged complexes of formula .The structure of <(C5Me5)ClRh(μ-Cl)(μ-PPh2)Rh(COD)>*1/2Et2O has been determined by X-ray diffraction methods.The complex consists of two moieties, (C5Me5)RhCl and Rh(COD), doubly-bridged by a diphenylphosphido group and a chlorine atom.The two rhodium atoms are separated by 3.3657(6) Angstroem.