G(HQ) = fG(p-OH-A) ×
k12,13[O ][p-OH-A]
2
(
19)
ϩ
k12,13[O ][p-OH-A] ϩ k [H ][p-OH-A]
2
7
ϩ
G(HQ)o
G(HQ)
k [H ]
(20)
7
Ϫ 1 =
k12,13[O2]
Here G(HQ) is the G value of hydroquinone formation in
o
ϩ
the absence (i.e. lowest H concentration at neutral pH) and
ϩ
G(HQ) in the presence of H . The term f denotes the fraction
of the reactions of the p-OH-adduct radicals (abbreviated as
p-OH-A) that leads to the formation of hydroquinone.
A plot of G(HQ) /G(HQ) Ϫ 1 vs. the proton concentration
o
3
3
(
Fig. 3) yields a straight line with a slope of 3.1 × 10 dm
mol . Taking k12,13(O ϩ p-OH-A) = 1.2 × 10 dm mol
see above), k = 1.0 × 10 dm mol
Ϫ1
9
3
Ϫ1 Ϫ1
Fig. 3 Proton concentration dependence of the term G(Product)o/
G(Product) Ϫ 1 in the γ-radiolysis of a N O–O (4:1)-saturated solution
s
2
9
3
Ϫ1
Ϫ1
2
2
(
s
is obtained. The
7
of phenol, (᭹) Product = hydroquinone, (᭺), Product = catechol.
analogous plot for the formation of catechol is also shown in
8
3
Fig. 3, and based on the same assumptions k = 2.1 × 10 dm
6
Ϫ1 Ϫ1
from phenol to ozone, or whether a phenol–ozone adduct is
mol
s
is obtained. The value of k obtained in this way is
7
ϩ 9 3 Ϫ1
Ϫ
ؒ
2
formed, which releases O
/HO
to react with ozone yielding
3 Ϫ1 Ϫ1 7
2
somewhat lower than the value [k(H ) = 1.7 × 10 dm mol
fast
Ϫ
Ϫ
9
Ϫ1
O
[k(O
3
2
ϩ O
3
) = 1.6 × 10 dm mol s ].
Considering the fast elimination of O
s ] obtained above by pulse radiolysis, but is in good agree-
ment with the reported value for k(dehydration) (~1 × 10 dm
mol s ) of the p-dihydroxycyclohexadienyl radicals. On the
Ϫ
2ؒ
9
3
2
/HO from the
Ϫ1 Ϫ1
3
peroxyl radicals formed upon dioxygen addition to the OH-
adduct radicals of phenol, a chain reaction can be induced.
This makes it difficult to assess without further experiments the
primary yield of the OH-radical-forming process. According to
our scavenging experiments with tert-butyl alcohol the overall
other hand, the value of k obtained here is higher than the
6
ϩ
value of k(H )
obtained above by pulse radiolysis and the
slow
8 3 Ϫ1 Ϫ1 3
reported value (both ~1 × 10 dm mol s ) for the dehydra-
tion of the o-dihydroxycyclohexadienyl radicals.
ؒ
contribution of OH to phenol degradation is ~30%.
It is noted that the yields using dioxygen as an oxidant are
ؒ
ؒ
lower (catechol 40% of OH, hydroquinone 31% of OH) than
when p-benzoquinone was used to oxidize the dihydroxycyclo-
Acknowledgements
This work has been partly supported by the BMBF project
ؒ
hexadienyl radicals (catechol 48% of OH, hydroquinone 36%
ؒ
3
of OH). This relative difference of 13% is significant (i.e. not
0
2WT9656/6. E. M. would like to thank the German Academic
within experimental error), and we conclude that in the case
ؒ
Exchange Service (DAAD) for a stipend.
of dioxygen other reactions besides HO -elimination reactions
2
may proceed, albeit to a much lower extent than observed with
2
5
34
other aromatic compounds, e.g., benzene or terephthalate.
References
25
In the benzene study, material balance has been obtained,
and from the products that are formed under these conditions
it has been concluded that peroxyl radicals of the kind formed
in reactions (12) or (13) can also undergo intramolecular
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8
48.
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3
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2
endoperoxide formation and subsequent fragmentation. In the
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3495.
ؒ
present system, the HO -elimination is so fast that this process
2
will contribute less to the overall decay processes.
4 E. J. Land and M. Ebert, Trans. Faraday Soc., 1967, 63, 1181.
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M. Roder, L. Wojnarovits, G. Földiak, S. S. Emmi, G. Beggiaro and
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Relevance for the reaction of ozone with phenol
6
7
In the ozonation of phenol in aqueous solutions, catechol
20
and hydroquinone are major products. At neutral pH, their
8
9
formation is suppressed when tert-butyl alcohol (which has a
7
ؒ
very low reactivity towards ozone) is added to scavenge OH.
Upon lowering the pH, the hydroquinone and catechol yields
7
9, 2587.
10 Y. Yamamoto, E. Niki, H. Shiokawa and Y. Kamiya, J. Org. Chem.,
1979, 44, 2137.
ؒ
decrease (hydroquinone more affected), as in the case of OH
1
1
1
1 P. C. Singer and M. D. Gurol, Wasser ’81 [Einundachtzig], 1981,
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2 J. A. Roth, W. L. Moench and K. A. Debalak, J. Water Pollut.
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(
see above). At pH 2, their formation ceases completely. This
ؒ
strongly points to the importance of OH in the ozonation
of phenol. Similarly, but to a lesser extent, OH formation has
ؒ
also been observed in the reaction of ozone with some tertiary
35
ؒ
amines. When OH reacts with tert-butyl alcohol, formalde-
ؒ
36,37
hyde is formed in yields close to 30% with respect to OH.
In
1
1
1
1
the ozonation of phenol in the presence of tert-butyl alcohol,
we found that the formaldehyde yield (~10% with respect to
ozone reacted with phenol/phenolate) did not change notice-
ؒ
ably with pH. This is a strong indication that OH formation is
due to the reaction of ozone with phenol and, as such, does
not require the presence of phenolate in equilibrium in the
19 S. Beulker and M. Jekel, Ozone: Sci. Eng., 1993, 15, 361.
20 E. Mvula and C. von Sonntag, unpublished results.
2
2
2
1 F. Muñoz, E. Mvula, S. Braslavsky and C. von Sonntag,
unpublished results.
2 C. von Sonntag and H.-P. Schuchmann, in Peroxyl Radicals,
ed. Z. B. Alfassi, Wiley, Chichester, 1997, p. 173.
3 K. Sehested, J. Holcman, E. Bjergbakke and E. J. Hart, J. Phys.
Chem., 1987, 91, 2359.
solution [pK (phenol) = 10; note that the rate constants of
a
phenolate and phenol differ by six orders of magnitude, i.e.
phenolate reactions may dominate down to fairly low pH
values]. However, one open question remains, that is whether
Ϫ
ؒ
O3
(precursor of OH) is formed directly by electron transfer
J. Chem. Soc., Perkin Trans. 2, 2001, 264–268
267