
Journal of Heterocyclic Chemistry p. 291 - 295 (2000)
Update date:2022-08-11
Topics:
Vittimberga, Bruno M.
Sears, Donald F.
When 6-phenanthridinecarbonitrile (3) is irradiated at 2537 A in neutral 9:1 2-propanol/water, three major products are formed. These are dimethyl-(6-phenanthridinyl)methanol (4), phenanthridine (5) and 6,6'- biphenanthridine (6). When benzophenone is present in the reaction mixture, diphenyl-(6-phenanthridinyl)methanol is also formed. 6-Phenanthridinyl radical which is common to the formation of all these products, is formed by a monophotonic process involving hydrogen atom abstraction from an alcohol molecule by an excited state of 3. Unlike what is generally found with other nitrogen-heterocycles, the photochemistry of 3 appears to involve only a π,π* singlet state. The fluorescence of 3 is quenched with the triplet quencher cis/trans-piperylene as a function of the concentration of the diene without the accompaniment of an exciplex emission.
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Doi:10.1039/a909484i
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