I.-H. Um et al.
Bull. Chem. Soc. Jpn. Vol. 86, No. 6 (2013)
739
M
S
Sδ
EtO Pδ
Ph
O
O
Ph P O
Me
Mδ
O
δ
δ
δ
Me P O
Me
NO2
NO2
EtO P O
Ph
NO2
NO2
OEt
TS1
OEt
TS2
6
7
Chart 3.
Chart 2.
Role of M+ Ions and TS Structures. M+ ions would
catalyze the reaction of 5 with EtOM either by increasing
the electrophilicity of the reaction center through TS1 or by
enhancing the nucleofugality of the leaving group via TS2
(Chart 2). However, the enhanced nucleofugality through TS2
would be ineffective if the leaving group departure occurs after
the rate-determining step (RDS). The mechanism of the current
reaction has not been investigated. However, it is apparent
that the leaving group departure would occur after the RDS, if
the current reaction proceeds through a stepwise mechanism.
would interact strongly with Li+ ion but would exhibit a weak
interaction with 18C6-complexed K+ ion. This idea is con-
sistent with the kinetic results that the P=O/EtOLi and P=S/
EtOK-18C6 reactions are catalyzed whereas the P=S/EtOLi
reaction is inhibited as mentioned above.20
Factors Governing Reactivity: Steric Hindrance vs.
Electronic Effects. Steric hindrance has been suggested to
be an important factor that governs the reactivity of organo-
phosphorus compounds toward anionic nucleophiles such as
¹
¹ 6b,21,22
OH and EtO .
Cook et al.21 and Hawes et al.22 have
¹
This is because the incoming EtO is significantly more basic
found that the rate of alkaline hydrolysis of a variety of alkyl
phosphinates decreases significantly with increasing the steric
bulk of the alkyl substituent attached directly to the central P
atom. A similar result has recently been reported for alkaline
ethanolysis of 4-nitrophenyl diphenylphosphinate (1), 4-nitro-
phenyl methyl phenylphosphinate (6), and 4-nitrophenyl di-
methylphosphinate (7) (Chart 3).6b Buncel and his co-workers
have shown that the replacement of the Ph groups in 1 by one
Me group (1 ¼ 6) or by two Me groups (1 ¼ 7) causes a
systematic increase in reactivity of the series (i.e., 1 < 6 < 7).6b
Since it is evident that a Ph group would exert a stronger steric
hindrance than a Me group on the basis of the steric substituent
constant (i.e., Es = 0 and ¹2.55 for Me and Ph, respectively),23
the steric hindrance has been concluded to be an important
factor that determines the reactivity of the P=O centered
electrophiles 1, 6, and 7.6b
and a poorer nucleofuge than the leaving 4-nitrophenoxy ion.
Thus, TS2 cannot be responsible for the M+ ion catalysis if the
reaction proceeds through a stepwise mechanism. On the con-
trary, if the reaction proceeds through a concerted pathway, M+
ions would catalyze the reaction either through TS1 or via TS2.
We have recently reported that alkaline ethanolyses of
Y-substituted-phenyl diphenylphosphinates including 114 and
Y-substituted-phenyl diphenylphosphinothioates including 24
proceed through a concerted mechanism from various LFER
studies (e.g., Brønsted-type, Hammett and Yukawa-Tsuno
equations). Besides, alkaline hydrolysis of 1 and aminolysis
of 1, 2, and 3 have also been reported to proceed through a
concerted pathway.15-18 Accordingly, there is a high possibility
that the reaction of 5 with EtOM would proceed through a
concerted mechanism with a transition-state structure similar
to TS1 or TS2.
Table 3 shows that the second-order rate constant for the
If the catalytic effect of M+ ions originates from an increase
in the nucleofugality through complexation of M+ ions with
the O atom in the leaving 4-nitrophenoxide ion (i.e., TS2), one
might expect that the effect of M+ ions should be similar to that
reported for the corresponding reactions of the P=O centered
electrophiles (e.g., 1 and 3). This is because the leaving group
for these substrates is identical (i.e., 4-nitrophenoxide ion).
In fact, the effect of M+ ions for the current reaction of 5 is
analogous to that reported for the reactions of the P=S centered
electrophiles 2 and 4, but contrasts to that reported for the
corresponding reactions of the P=O centered electrophiles 1
and 3 (e.g., the reactivity of EtOM increases in the order
reaction of 5 with EtO (i.e., kEtO ) is ca. 2.65 © 10¹3 M¹1 s
,
¹
¹1
ꢀ
which is smaller than kEtO = 14.0 © 10¹3 M¹1 s for the
corresponding reaction of 24 but is much larger than kEtO
¹1
ꢀ
ꢀ
=
¹1
5.06 © 10¹5 M¹1 s for the reaction of 4.5a The reactivity of
these substrates would be influenced by the steric hindrance
and/or by the electronic effects of the Ph and EtO groups in
the nonleaving group of substrates 2, 4, and 5 (e.g., Ph2P=S,
(EtO)2P=S, and Ph(EtO)P=S for 2, 4, and 5, in turn). The Es
value for the EtO group is not available but it would be similar
to the Es value of ¹0.36 for the n-Pr group.23a It is apparent that
2 would experience a stronger steric hindrance than 4 and 5,
since -Es = ¹5.10 for the two Ph groups in 2, -Es = ¹2.91
for the Ph and EtO groups in 5 and -Es = ¹0.72 for the two
EtO groups in 4. Accordingly, 2 is expected to be less reac-
tive than 4 and 5, if the steric effect is an important factor to
affect their reactivity. However, as mentioned above, 2 is more
reactive than 4 and 5, indicating that the steric hindrance cannot
be responsible for the reactivity order found for these P=S
electrophiles. Interestingly, this is in contrast to the reports that
the steric hindrance is the most important factor that governs
the reactivity of the P=O centered electrophiles (e.g., 1, 6,
and 7).6b,21,22
¹
EtO < EtOK < EtONa < EtOLi for reactions of 1 and 3 but
¹
EtOLi < EtO < EtONa < EtOK for the reactions of 2 and
4).3-5 Therefore, the contrasting M+ ion effects found for the
reactions of the P=O and P=S centered electrophiles indicate
that the reaction proceeds through TS1 rather than TS2.
One might account for the contrasting M+ ion effects in
terms of the hard and soft acids and bases (HSAB) principle.19
According to the HSAB principle, the P=S centered electro-
phile 5 (a soft Lewis acid) would interact weakly with Li+
ion (a hard Lewis acid) but would exert a strong interaction
with the 18C6-complexed K+ ion (a soft Lewis acid). On the
contrary, the P=O electrophiles 1 and 3 (a hard Lewis acid)
Then, one might suggest that the reactivity of the P=S
centered electrophiles would be governed by electronic effects