2820
Organometallics 2000, 19, 2820-2822
Rea ction of KIn (CH2CMe3)3H w ith
Ch lor od ip h en ylp h osp h in e
O. T. Beachley, J r.* and Sun-Hua L. Chao
Department of Chemistry, State University of New York at Buffalo,
Buffalo, New York 14260-3000
Received J anuary 10, 2000
Summary: The reaction between KIn(CH2CMe3)3H and
ClPPh2 in pentane or benzene produces significant yields
of two indium-phosphorus compounds, (Me3CCH2)2-
InPPh2 and (Me3CCH2)3In‚P(CH2CMe3)Ph2. This unex-
pected adduct incorporates a neopentyl group that was
originally a substituent on the indium reagent. The other
products of the reaction are CMe4, H2, and KCl. The
formation of all products is explained by a set of
experimentally verified reactions.
not require the prior synthesis and handling of HPR′2.
Ideally, the secondary phosphine should be formed in-
situ and then be consumed by reaction with the organo-
indium compound. This goal was realized with the
synthesis of [(Me3CCH2)2InP(t-Bu)2]2 in high, if not
quantitative, yield by reacting KIn(CH2CMe3)3H6 with
ClP(t-Bu)2 in pentane (eq 2).7 In contrast, we have found
KIn(CH2CMe3)3H + ClP(t-Bu)2 pentane8
(Me3CCH2)2InP(t-Bu)2 + KCl + CMe4 (2)
In tr od u ction
The original and simplest route to compounds of the
type R2InPR′2 involves the use of the hydrocarbon
elimination reaction1-3 between InR3 and HPR′2. Even
that the reaction between KIn(CH2CMe3)3H and ClPPh2
forms a different set of products and thus involves some
reactions that were not observed for the tert-butyl
phosphine system.7
InR3 + HPR′2 hydrocarbon elimination8 R2InPR′2 + RH (1)
reaction
Resu lts a n d Discu ssion
though the metathetical reaction4 between InR2Cl and
LiPR′2 and the Me3SiCl elimination reaction5 between
InR2Cl and (Me3Si)PR′2 have also been exceedingly
useful and productive reactions to prepare R2InPR′2, the
latter reactions require the synthesis of more starting
materials than are needed for the simple hydrocarbon
elimination reaction. Therefore, a goal of our research
has been to develop a procedure for the preparation of
R2InPR′2 that would take advantage of the simplicity
of the hydrocarbon elimination reaction but that would
The reaction between KIn(CH2CMe3)3H and ClPPh2
in either pentane or benzene produces two indium-
phosphorus compounds (Me3CCH2)2InPPh22,3 and (Me3-
CCH2)3In‚P(CH2CMe3)Ph2, which account for approxi-
mately 85-90% of the initial indium and phosphorus.
The other products that were isolated from the reaction
included CMe4, H2, and KCl. The identity of the
principal product (Me3CCH2)2InPPh2 was confirmed by
1
observing that its physical properties as well as its H
and 31P NMR spectra were identical with those for
samples prepared by the elimination reaction between
In(CH2CMe3)3 with HPPh2 in pentane or benzene solu-
tion.2,3 Thus, (Me3CCH2)2InPPh2 has been synthesized
directly from the chlorophosphine without the interme-
diate preparation and isolation of HPPh2. The second
indium-phosphorus product is (Me3CCH2)3In‚P(CH2-
CMe3)Ph2, an adduct of a tertiary phosphine that
contains a neopentyl group that was a substituent on
the initial indium reagent. The 1H and 31P NMR spectra
of this adduct were identical with those of a sample
prepared from a 1:1 mixture of In(CH2CMe3)3 and
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10.1021/om000017q CCC: $19.00 © 2000 American Chemical Society
Publication on Web 06/06/2000