Journal of Organometallic Chemistry p. 97 - 108 (2001)
Update date:2022-07-29
Topics:
Riera, Xavier
Caubet, Amparo
López, Concepción
Moreno, Virtudes
Freisinger, Eva
Willermann, Michael
Lippert, Bernhard
The reaction of ligand C6H5-CH=N-CH2-CH2-SEt (1) with Na2[PdCl4] is studied. It yields, depending on the experimental conditions, two different sorts of palladium(II) complexes: cis-[Pd{C6H5-CH=N-CH2-CH 2-SEt}Cl2] (2b) and [Pd{C6H4-CH=N-CH2-CH2-SEt}Cl] (3b). Compounds 2b and 3b differ in the mode of binding of the ligand to the palladium: as a neutral (N,S) group in 2b or as a monoanionic (C,N,S)- terdentate ligand in 3b. The results presented here show that the formation of 3b is promoted thermally and requires the presence of sodium acetate. The cyclopalladated complex 3b reacts with PPh3, in a 1:1 or 1:2 molar ratio, to produce [Pd{C6H4-CH=N-CH2-CH 2-SEt}Cl(PPh3)] (4b) or [Pd{C6H4-CH=N-CH2-CH 2-SEt}Cl(PPh3)2] (5b), respectively. All the complexes have been characterised by elemental analysis, infrared and NMR spectroscopy. Compounds 2b and 3b have also been characterised structurally: 2b is triclinic, space group P1?, with a=8.081(2), b=8.230(2), c=10.836(2) ?, α=109.16(3), β=96.65(3) and γ=92.29(3)° and 3b is triclinic, space group P1?, with a=10.201(2), b=11.927(2), c=17.568(4) ?, α=104.35(3), β=94.21(3) and γ=111.56(3)°. The structural studies confirmed the mode of binding of the ligand to the palladium and revealed that the ligand has the Z-form in 2b and the E-form in 3b. Semiempirical calculations based on the pm3(tm) method have also been used to explain the isomerisation of 2b.
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