Journal of Organometallic Chemistry p. 177 - 184 (1981)
Update date:2022-08-04
Topics:
Miller, Jack M.
Chadha, Raj K.
RTeCl3 (R=C6H5, p-CH3OC6H4 or p-C6H5OC6H4) reacts with Me3SiNR'2 (R'2=Et2, C4H8) under dry nitrogen atmosphere to give R(R'2N)TeCl2 and Me3SiCl.The products readily decompose to give (R'2NH2)+(RTeCl4)-.The products have been characterized by 1H NMR, IR and mass spectra.R2TeCl2 does not react with Me3SiNR'2 even on refluxing for 6 h.Et2NLi, however, reduces R2TeCl2 to R2Te.
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