
Journal of Chemical Thermodynamics p. 1165 - 1171 (2006)
Update date:2022-08-11
Topics:
Tewari, Yadu B.
Kishore, Nand
Rozzell, J. David
Vanderah, David J.
Schantz, Michele M.
The equilibrium constants K for the reactions (1-phenyl-1-alkanone + 2-propanol = 1-phenyl-1-alkanol + acetone) in the solvents n-pentane and n-hexane have been determined by using gas chromatography at the temperature 298.15 K. The 1-phenyl-1-alkaones included in this study were: 1-phenyl-1-ethanone, 1-phenyl-1-propanone, 1-phenyl-1-butanone, 1-phenyl-1-pentanone, 1-phenyl-1-hexanone, and 1-phenyl-1-heptanone. The equilibrium constants for the reaction involving 1-phenyl-1-ethanone were measured in the solvent n-hexane as a function of temperature (288 K to 308 K). The calculated thermodynamic quantities for the 1-phenyl-1-ethanone reaction at T = 298.15 K are: K = 0.2177 ± 0.0018; the standard molar Gibbs free energy change, Δr Gm{ring operator} = (3.78 ± 0.02) kJ · mol- 1, the standard molar enthalpy change, Δr Hm{ring operator} = (4.53 ± 0.87) kJ · mol- 1, and the standard molar entropy change, Δr Sm{ring operator} = (2.5 ± 2.9) J · K- 1 · mol- 1. The equilibrium constants of 1-phenyl-1-alkanone with an odd number of carbons in alkyl side chain are higher than the equilibrium constants of the preceding 1-phenyl-1-alkanone having an even number of carbons in the side chain and follow a zig-zag pattern with increasing carbon number in the alkyl side chain.
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