1992
Ming Zhou et al. / Chinese Journal of Catalysis 36 (2015) 1987–1994
sonic irradiation, which come from the thermal dissociation of
water molecules by the local high temperature and pressure
[3]. However, the amount of OH radicals produced without
4. Conclusions
•
Bar‐ and cube‐like LuFeO3 particles were synthesized via a
hydrothermal route. The as‐synthesized particles exhibit good
sonocatalytic activity toward the degradation of AO7, RhB, MO,
and MB under ultrasonic irradiation. The highest sonocatalytic
activity is observed for the bar‐like particles with lengths of ~3
μm and widths of ~1 μm, where the degradation percentage of
AO7 reaches 89% after sonocatalysis for 30 min. The inorganic
catalyst is negligible compared with the amount produced over
the ultrasonic‐irradiated LuFeO3 particles.
3.10. Possible reaction mechanism
The sonocatalysis is initiated by exciting LuFeO3 through
hot spots and/or sonoluminescences, during which electrons
are excited from the valence band of LuFeO3 to its conduction
band, thus creating electron‐hole (eCB−‐hVB+) pairs (Eq. (1)). The
sonogenerated electrons and holes migrate to the LuFeO3 par‐
ticle surface and participate in a series of redox reactions to
produce active species. Based on the experimental results and
analysis, •OH radicals are suggested to be the main active spe‐
cies responsible for the dye degradation over the ultrason‐
ic‐irradiated LuFeO3 particles. It is well known that the redox
reaction to produce active species is highly dependent on the
CB and VB edge potentials of the semiconductor. According to
the Refs. [28–30], the CB and VB edge potentials of LuFeO3 are
calculated to be −0.08 and +2.06 V versus normal hydrogen
electrode (NHE), respectively. Figure 10 schematically shows
the band potentials of LuFeO3 and its sonocatalytic mechanism
toward the dye degradation. The redox potentials of H2O/•OH
and OH−/•OH are +2.72 and +1.89 V versus NHE [31], which are
positive and negative to the VB potential of LuFeO3, respective‐
ly. From a thermodynamic point of view, the sonogenerated
hVB+ can react with OH− (but cannot with H2O) to produce •OH
radicals (Eq. (2)). The redox potential of O2/H2O2 is +0.695 V
[32], which is positive relative to the CB potential of LuFeO3,
indicating that •OH radicals can also be produced through Eqs.
anions Cl−, NO3 , SO42−, PO43−, and HCO3− have an inhibitive ef‐
−
fect on the sonocatalytic degradation of the dye, but the catalyst
maintains a high sonocatalytic activity. The addition of ethanol
•
leads to substantial suppression of the dye degradation. OH
radicals are found to be produced over the ultrasonic‐irradiat‐
ed LuFeO3 particles and are quenched with the addition of
ethanol. Based on the experimental results, it is suggested that
•OH radicals are the primary active species in the sonocatalysis.
LuFeO3 particles also exhibit good sonocatalytic reusability.
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•
(3) and (4). OH radicals attack the double bonds of dissolved
dye molecules, thus destroying the dyes (Eq. (5)).
+
LuFeO3 + US
hVB+ + OH−
2eCB− + O2 + 2H+ → H2O2
eCB− + H2O2
→ LuFeO3 (eCB− + hVB
→ OH
)
(1)
(2)
(3)
(4)
(5)
•
•
→ OH + OH−
•OH + dye
→ degradation products
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Dye
-2.0
-1.5
-1.0
-0.5
0.0
0.5
1.0
1.5
2.0
2.5
3.0
3.5
4.0
Products
-
O2+H
H2O2 OH
Sudden collapse of
the cavitation bubbles
e- e- e- e-
O /
O
= -0.13
2
ECB = -0.08
US
O /H O = 0.695
2
2 2
Hot spots
Sonoluminescence
-
OH / ·OH = +1.89
= +2.06
h+ h+ h+ h+
E
VB
OH
-
OH
H O/ ·OH = +2.72
2
Products
Dye
LuFeO3 catalyst
[22] Zhou M, Yang H, Xian T, Li R S, Zhang H M, Wang X X. J Hazard
Mater, 2015, 289: 149
Fig. 10. Schematic illustration of the sonocatalytic mechanism of
LuFeO3 particles toward the dye degradation.