Organic Letters
Letter
aliphatic alcohols prevented us from running their reaction in
an open reactor, we identified suitable closed reactor
conditions incorporating styrene as a hydrogen acceptor.
Introduction of the N-benzylamino group of 8 is not simply
a strategy for improved yield: it is a versatile protecting group
that enables differential substitution of this nitrogen through its
convenient cleavage. While this deprotection has a potential
complication of opening the newly formed piperidine ring, we
find chemoselective cleavage of 11 with hydrogen and Pd/
BaSO4 to give 10 in 80% yield upon screening various
heterogeneous hydrogenation catalysts (Table S6).
While our results demonstrate a unique combination of
hydrogen borrowing amination conditions and the PSR, we
thought it prudent to check whether the few other known
hydrogen borrowing catalysts might also affect the tandem
process. We screened iridium homologues of 1, complexes 2
and 3 (Figure 1),21 and base-free amination catalysts17c,d
[Cp*IrCl2]2 and [Cp*IrI2]2. We found that each of these
complexes returns starting materials, octanol and 8, under the
tandem conditions. Thus, ruthenium complex 1 is the only
catalyst we find for the tandem sequence.
mechanism accounts for the crucial role of the Lewis acid and
explains the distribution of products 10 and 11 observed in
Table 2.
When the reaction proceeds from N-benzyltryptamine 8, it
can take only one pathway (highlighted on the right of Scheme
1). This sequence starts with the formation of iminium ion 8a,
followed by cyclization to give 8b. This formal iminium ion is
more electrophilic than the imine involved in the parent
sequence. We perceive that this is one of the advantages of N-
benzyltryptamine as a substrate for the tandem reaction. This
sequence proceeds without an acid catalyst, albeit at lower
yield (compare 32% to 73% (Table 4)), so indium is important
Table 4. Substituting MgSO4 for In(OTf)3 in the Tandem
Sequence
Since 8, a secondary amine, is a convenient substrate for our
reaction, the intermediate iminium ion resulting from its
condensation with an aldehyde need not be further activated to
enable cyclization. By contrast, imine of the parent tryptamine
must be activated by a proton or Lewis acid. Oddly, reactions
of 8 retain the need for the In(OTf)3 cocatalyst, so we went
about studying the mechanism22 of our reaction to identify the
role of the Lewis acid. We recently reported in detail the role
of the metal catalyst in the amination,16m so we limit this
discussion to the sequence of organic intermediates in the
tandem process.
product and
a
entry
1
X
Y
conditions
yield
H
H
H
1 mol % 1, 1 equiv of MgSO4, neat, 11 (20%)
110 °C, 24 h
b
2
3
4
5
6
H
H
H
1 mol % 1, 10 mol % In(OTf)3,
neat, 110 °C, 24 h
1 mol % 1, no In(OTf)3, neat,
110 °C, 24 h
1 mol % 1, 10 mol % In(OTf)3,
toluene, reflux, 96 h
11 (79%)
11 (32%)
11 (73%)
CH2Ph
CH2Ph
CH2Ph
CH2Ph
b
b
Br 1 mol % 1, 10 mol % In(OTf)3,
toluene, reflux, 96 h
Br 1 mol % 1, 1 equiv of MgSO4,
toluene, reflux, 96 h
12c (78%)
12c (74%)
Pathways for the reactions starting from tryptamine (7) and
N-benzyltryptamine (8) are shown in Scheme 1. In the first,
a
b
NMR yield with mesitylene as the internal standard. Isolated yield.
Scheme 1. Proposed Mechanisms for the Tandem Sequence
but nonessential. When catalytic indium is replaced with 1
equiv of MgSO4 in the reaction of 8 with 4-bromobenzyl
alcohol, we see similar yields, 78% and 74%. In contrast, the
parent tryptamine cyclization yielded product 11 in 20% yield
with MgSO4 compared to 79% with catalytic In(OTf)3. We
speculate that the role of indium or magnesium in reactions of
8 could be a dehydrating agent driving iminium formation,
rather than Lewis acid promoting iminium activation.
Unlike the parent tryptamine reaction, two products are
possible when N-benzyltryptamine reacts with an alcohol,
because either the starting N-benzyl group or the added
alcohol could potentially participate in the cyclization. We
observe one product,23 which has only the added alcohol
participating in cyclization. Isotopic labeling supports this
point (Scheme 2): reaction of 8 and benzyl alcohol-d3, 6-d3,
tryptamine undergoes condensation with benzaldehyde,
generated in situ, to form 9. It can either undergo ring closure
in the presence of indium triflate to afford 10 or be reduced to
8. We compared the relative rates of these potentially
competing reactions by analyzing the product distribution in
the reaction between 9 and 4-fluorobenzyl alcohol under the
catalytic conditions (Scheme S1). We found that 9 converts to
a mixture of 36% of 10 and 38% of 10b and 8b together, where
Ph′ is a fluorophenyl group. This indicates that under the
tandem conditions both 10b and 8b are formed and that the
cyclization step (9 to 10) is faster than the imine reduction (9
to 8) and the second amination step (10 to 10b). This
1
gives 11-d1 along with its H isotopolog (ca. 25%), but no
other labeled species. A 2H NMR spectrum (Figure S15) of the
isolated product shows a singlet at 4.67 ppm corresponding to
2
the aliphatic CD position of 11-d1. No H is observed at the
Scheme 2. Deuterium Labeling Experiment
C
Org. Lett. XXXX, XXX, XXX−XXX