Acta Crystallographica, Section C: Crystal Structure Communications p. 1616 - 1618 (1996)
Update date:2022-07-30
Topics:
Hoffman, David M.
Rangarajan, Sri Prakash
NbBr5 reacts with three equivalents of Me3SiNPh2 in ether to give the title compound, [NbBr2(C12H10N)3].-C 4H8O. Nb(NPh2)3Br2 has trigonal bipyramidal geometry with axial bromide ligands.
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