
Journal of Organometallic Chemistry p. 271 - 278 (1998)
Update date:2022-08-05
Topics:
Gibbons, Martin N.
Sowerby, D. Bryan
Reactions of [SbPh3Br]2O and [SbMe3Cl]2O with a number of carboxylates lead to halogen substitution and formation of either [SbR3(O2CR′)]2O or SbR3(O2CR′)2. X-ray structures for two of the products, [SbPh3(O2CCF3)]2O and [SbMe3(O2CCH3)]2O, show that the carboxylates are unidentate. From NMR spectroscopy, the oxygen bridged compounds are hydrolysed by adventitious water giving SbR3(O2CR′)OH in solution but when R = phenyl the original compounds can be recovered on crystallisation.
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