TEST FOR CAUSALITY
1489
Ž
.
Ž
.
p
whereas, by C9, C p q yC is
j
1yr2
1yr2
ϱ
j
j
j
j
yi
l
p
˜
Ž
.
Ž
.
Ž
.
Ž
.
B.5
2
l c l
e
qO
s 2
Cp qO
,
Ý
ž T /
ž /
T ž
/
T
ž
/
T
l
sy
ϱ
ϱ
l
yi
l
p
˜
Ž
.
Ž
.
Ž
.
p
where Cp sÝ sy ϱ l c l e
. Thus, adding and subtracting C p q yC into the first
j
term on the right of B.3 and using B.4 , B.5 and Ýmjsym js0, the right side of B.3 is
Ž
.
Ž
.
Ž
.
Ž
.
y1
y2q r2
˜
Ž
.
Ž
.
.
4 Mp
Cp qO M
Q.E.D.
REFERENCES
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.
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