Crystal Growth and Design p. 700 - 708 (2010)
Update date:2022-07-30
Topics:
Antelo, Jose M.
Adrio, Luis
Teresa Pereira
Ortigueira, Juan M.
Fernandez, Jesus J.
Vila, Jose M.
Treatment of 4-MeOC6H4C(Me)=NN(H)C(=S)NHMe (1), with potassium tetrachloropalladate gave the tetranuclear compound [Pd{4-MeOC 6H3C(Me)=NN=C(S)NHMe}]4 (2), with the ligand as terdendate [C,N,S]. Reacti
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