L. Zhou et al. / Journal of Molecular Catalysis A: Chemical 388–389 (2014) 74–80
77
3.2. Effect of base on glucose conversion to MLA catalyzed by
SnCln
1.0
0.8
0.6
0.4
0.2
0.0
SnCl4
NaOH
SnCl4+0.2NaOH
SnCl4+0.4NaOH
SnCl4+0.8NaOH
SnCl4+1.0NaOH
SnCl4+1.2NaOH
SnCl4+1.4NaOH
At first, NaOH was used to adjust the acidity of the reaction
solution. The effect of NaOH amount on the pH value of methanol
solution of SnCl4, glucose conversion, and product yields are shown
in Fig. 2. The conversion of glucose was complete at 160 ◦C for 2.5 h,
which was independent of the catalyst (either SnCl4 or SnCl2) and
the amount of NaOH. With SnCl4 as catalyst, the MLA yield gradually
increased with NaOH amount until the molar ratio of NaOH/SnCl4
was 1.0, where the MLA yield was 47%. Subsequently, the MLA yield
slowly decreased with further increase in NaOH amount. In com-
parison with MLA, the MLE yield decreased constantly with the
increase of NaOH amount. The yields of MLA and MLE over SnCl2
changed similarly as those over SnCl4 with the increase of NaOH
amount. The difference was that the maximum yield of MLA (40%)
of SnCl2 were less than that of SnCl4.
200
220
240
260
280
300
Wavelength (nm)
Fig. 3. UV-vis spectra of SnCl4 (0.27 mmol/L) in methanol with the addition of NaOH
(the numbers in the names denote the molar ratio of NaOH/SnCl4.)
It has been reported that inorganic bases such as NaOH, KOH,
and Ca(OH)2 can catalyze glucose conversion to lactic acid in water
[9,25]. However, the MLA yield is only 5% using NaOH as the sole
catalyst under the present reaction conditions (Table 1, entry 20).
The pH value of the methanol solution of SnCl4 increased gradually
with the increase of NaOH amount (Fig. 2a), indicating that NaOH
neutralized the protons derived from the hydrolysis/methanolysis
of SnCln. So, the dehydration reaction of hexose to HMF and its
derivatives was suppressed effectively, which no longer competed
drastically with the retro-aldol condensation reaction of hexose to
form MLA. Thus, the yield of MLA increased. Meanwhile, the neu-
tralization of protons with NaOH also restrained the reaction of
pyruvaldehyde with methanol which would have produced pyru-
valdehyde dimethylacetal because the reaction was considered to
be catalyzed by Brønsted acid sites [26–28], which also contributed
[Sn(H2O)5(OH)]3+ was gradually consumed due to further hydroly-
sis in the presence of excess NaOH. The change of Sn species behaves
like that of Au species with the increase of the solution pH [37]. So,
the MLA yield increased first and then decreased with the increase
of NaOH amount.
The aforementioned water for hydrolysis of metal salts in the
reaction solution originated from (1) water of crystallization in
SnCl4·5H2O and glucose monohydrate; (2) water adsorbed by the
raw materials including methanol, SnCl4·5H2O, and NaOH; (3)
water formed in the dehydration reaction of glucose. The water
from these sources was probably enough for the hydrolysis of Sn
halide, because the conversion of glucose and the yield of MLA were
almost not affected when extra water was added into the solu-
tion. For example, when 6.7 wt% water was added into methanol,
the conversion of glucose (100%) and the yield of MLA (45%) were
(molar ratio of 1: 1) as catalyst.
To further validate the effect of base, other inorganic bases
such as KOH, Ca(OH)2, Ba(OH)2, NH3·H2O, and even solid base NaY
were utilized. The results of glucose conversion catalyzed by SnCl4
with different bases are exhibited in Table 2. All these bases could
promote MLA yield, but the behaviors of these bases were differ-
ent. Among these bases, the promotion effect of NaOH, KOH, and
Ba(OH)2 on the yield of MLA was more significant than Ca(OH)2,
NH3·H2O, and NaY. It implies that the strength of base determines
its performance. In addition, the solid base NaY improved not only
the MLA yield but also the MLE yield, which suggests that the intrin-
sic Brønsted acid sites of zeolite facilitated the formation of MLE.
Nevertheless, the MLA yield decreased when NaOH amount
exceeded a certain value, which implies that excess NaOH prob-
ably changes Sn species that are active for producing MLA. As
0 to 1.4. Metal salts can form different species in the solution
with different pH. For SnCl4, the mononuclear species [Sn(H2O)6]4+
[SnCl(H2O)5]3+, and [Sn(H2O)5OH]3+ have been proposed primarily
at pH < 2 [23,29–32]. [Sn(H2O)5(OH)]3+ with Sn-OH similar to the
open Sn sites in Sn-Beta zeolite was considered as the most active Sn
species for glucose isomerization to fructose [23,33–35]. It will be
shown below that fructose is more facile to produce MLA. Accord-
ing to the relationship of the thermodynamic equilibrium among
.
However, excess NaOH would render [Sn(H2O)5(OH)]3+ further
hydrolysis leading to the reduction of [Sn(H2O)5(OH)]3+ species.
yield (Table 1, entry 6), which confirms the importance of Sn species
in producing MLA.
Table 2
Glucose conversion in methanol catalyzed by SnCl4 with different basesa
UV-Vis spectroscopy analysis for SnCl4 in methanol with dif-
ferent amounts of NaOH to some extent reflected the change of
the status of Sn4+ (Fig. 3). SnCl4 in methanol possessed a strong
absorption band centered at 221.8 nm, which was assigned to the
electron transfer transition from Cl– ligand to Sn4+ center [36]. With
the increase in the amount of NaOH, the intensity of the absorp-
tion band weakened, suggesting that part of Cl–ions surrounding
Sn4+ center had been replaced by OH–ions. The more OH–ions were
incorporated, the more Cl–ions were replaced. So Sn species were
changed. Namely, the species [SnCl(H2O)5]3+ decreases accompa-
nied by the increase of the active species [Sn(H2O)5(OH)]3+. Finally,
Entry
Base
Glucose
conversion
(%)
Methyl
lactate
yield (%)
Methyl
levulinate
yield (%)
1
2
3
4
5
6
7
no
NaOH
KOH
Ba(OH)2
Ca(OH)2
NH3·H2O
NaY
100
100
100
100
100
100
100
28
47
45
48
35
37
35
20
6
8
16
5
3
22
a
Reaction conditions: glucose (1.72 mmol), SnCl4 (0.68 mmol), base (0.68 mmol)
except for NaY (0.1 g), methanol (15 mL), 160 ◦C, 2.5 h, 0.1 MPa N2.