Reaction of LiArMe6

Add time:08/08/2019    Source:sciencedirect.com

Indium(I)chloride reacts with LiArMe6 (ArMe6 = C6H3-2,6-(C6H2-2,4,6-Me3)2) in THF to give three new mixed-valent organoindium subhalides. While the 1:1 reaction of InCl with LiArMe6 yields the known metal-rich cluster In8(ArMe6)4 (1), the use of freshly prepared LiArMe6 led to incorporation of iodide, derived from the synthesis of LiArMe6, into the structures, to afford In4(ArMe6)4I2 (2) along with minor amounts of In3(ArMe6)3I2 (3). When the same reaction was performed in 4:3 stoichiometry, the mixed-halide compound In3(ArMe6)3ClI (4) was obtained. Further increasing the chloride:aryl ligand ratio resulted in the formation of the known mixed-halide species In4(ArMe6)4Cl2I2 that can also be obtained from the reaction of InCl with in situ prepared LiArMe6 in toluene. The new compounds 2 and 4 were characterized in the solid state by X-ray crystallography and IR spectroscopy, and in solution by UV/Vis and 1H/13C{1H} NMR spectroscopies. The structural characterization of 2 and 4 was supported by electronic structure calculations at the density functional level of theory which were also performed to rationalize the cluster-type bonding in 1.

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