
European Journal of Inorganic Chemistry p. 744 - 750 (2003)
Update date:2022-08-05
Topics:
Dey, Sandip
Jain, Vimal K.
Singh, Jaspreet
Trehan, Veena
Bhasin, Kuldip K.
Varghese, Babu
The reaction of py2Te2 or (3-MeC5H3N)2Te2 with Na2PdCl4 in methanol yields an insoluble brown complex, [PdCI(TeNC5H3R)]n (R=H or Me). Several reactions of pyTe-, (3-MeC5H3N)Te-, or (6-MeC5H3N)Te- with various palladium(II) and platinum(II) complexes have been carried out. Complexes of the types [MCl(Te-N)(PR3)], [Pt(Te-N)2(dppe)], [Pt(Te-N)2(PPh3)2], and [Pt2(μ-Te-N)2(dppe)2] [BPh4]2 [M=Pd or Pt; Te-N = pyTe, (3- or 6-MeC5H3N)Te] have been prepared and characterized by elemental analyses, UV/Vis, IR, and NMR (1H, 31p, 195Pt) spectroscopy. The complexes [MCl(Te-N)(PR3)] show irreversible oxidation and reduction by CV in DMF. The molecular structure of [PdCl{Te(3MeC5H3N)}(PPh3)] (2c) has been established by single-crystal X-ray diffraction analysis. The palladium atom is bound to the chelating 3-methylpyridinetellurolate ligand, a chlorine atom and a PPh3 ligand. The pyrolysis of [PdClTe(3MeC5H3N)}(PR3)] (PR3=PEt3 or PPh3) at 340 °C yields PdTe. Wiley-VCH Verlag GmbH & Co. KGaA, 69451 Weinheim, Germany, 2003.
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