868
Note
Table 1. Selected bond lengths and angles of the [CeF4-
(NH3)4] moleculea.
Tetraammine Tetrafluorido Cerium(IV)
Ammonia (1/1), [CeF4(NH3)4] · NH3
˚
Atoms
Ce(1)–F(1)
Ce(1)–N(1) 2.586(2)
N(1)–H(1A) 0.66(3)
N(1)–H(1B) 0.84(3)
Distance (A)
Atoms
Angle (deg)
2.1586(14)
F(1)#1-Ce(1)–F(1)#2 146.05(8)
F(1)#1-Ce(1)–F(1)#3 104.98(8)
Florian Kraus and Sebastian A. Baer
F(1)#1-Ce(1)–F(1)
84.95(8)
72.62(7)
AG Fluorchemie, Department Chemie,
Technische Universita¨t Mu¨nchen, Lichtenbergstraße 4,
85747 Garching, Germany
F(1)#1-Ce(1)–N(1)#1
N(1)–H(1C) 0.84(3)
a
F(1)#2-Ce(1)–N(1)#1 140.62(7)
Symmetry operations as in Fig. 1.
Reprint requests to PD Dr. Florian Kraus.
Fax: +49-89-289-13762. E-mail: fluorchemie@mytum.de
Table 2. Hydrogen bond parameters of the title compound
˚
(A, deg).
Z. Naturforsch. 2011, 66b, 868 – 870;
received June 24, 2011
D–H
H···A
2.35(3)
2.24(3)
2.60(3)
D···A
∠DHA
160(4)
177(3)
144(2)
N(1)–H(1A)···F(1)#4
N(1)–H(1B)··· F(1)#5
0.66(3)
0.84(3)
0.84(3)
2.975(3)
3.075(3)
3.315(4)
The synthesis and crystal structure of the first ammine
complex of a cerium fluoride, tetraammine tetrafluorido
cerium(IV) ammonia (1/1), [CeF4(NH3)4] · NH3, are pre-
sented. The compound crystallizes in the form of colorless,
block-shaped single crystals in the tetragonal space group
N(1)–H(1C)··· N(2)#6
a
Symmetry transformations for the generation of equivalent atoms:
#4
#5
#6
−x + 1, y + 1/2, −z; x − 1, −y + 1/2, z; −x + 1, y − 1/2,
−z+1/2.
˚
P4/ncc with a = 9.03215(9), c = 10.96404(17) A, V =
3
˚
894.443(19) A , and Z = 4. The compound contains discrete
[CeF4(NH3)4] molecules interconnected by N–H···F hydro-
gen bonds.
Key words: Cerium, Fluoride, Ammine, Crystal Structure,
Liquid Ammonia
Fig. 1. The [CeF4(NH3)4] molecule at 123 K. Displacement
ellipsoids are shown at the 70 % probability level, hydrogen
atoms with arbitrary radii. Symmetry transformations for the
generation of equivalent atoms: #1 −x+1, −y+1, −z+1/2;
Introduction
Metal fluorides dissolve only sparingly in liquid
ammonia and their chemistry is therefore little ex-
plored [1]. Biltz and coworkers used hydrates of flu-
orides to lower the lattice energy and hence to improve
their solubility in liquid ammonia [2]. The ammoni-
ates obtained in this way were analyzed using volume-
pressure measurements [3]. In our own investigations
on the reactions of fluorides with anhydrous ammo-
nia, we discovered that fluorides of the β-ZrF4 struc-
ture type, which is also known for the tetrafluorides
of the elements Hf, Ce, Th, U, Np, Pu, and Cm [4 – 7]
show appreciable solubility and form the isotypic com-
pounds [MF4(NH3)4] · NH3 (M = Zr, Hf, U) [8, 9]. To
our knowledge, the reaction of CeF4 with liquid am-
monia has not been investigated and we present here
the first structural evidence for the existence of ammine
complexes of cerium fluorides.
#2
−x+3/2, −y+1/2, z; #3 x−1/2, y+1/2, −z+1/2.
(NH3)4] · NH3 (see Table 4 for crystallographic de-
tails). As the title compound is isotypic to [MF4-
(NH3)4] · NH3 (M = Zr, Hf, U) [8, 9], a detailed struc-
tural description will not be given. The crystals con-
tain discrete [CeF4(NH3)4] molecules (Fig. 1) with
four Ce–F distances of 2.1586(14) and four U–N dis-
˚
tances of 2.586(2) A. Selected bond lengths and an-
gles are listed in Table 1. The molecules are intercon-
nected via N–H···F hydrogen bonds. These hydrogen
˚
bonds have H···F distances of 2.24(3) and 2.35(3) A
with N–H···F angles of 177(3) and 160(4)◦. Hydrogen
bonds from the ammine ligands to the nitrogen atom of
the crystal ammonia can also be inferred with an H···N
˚
distance of 2.60(3) A and an N–H···N hydrogen bond
angle of 144(2)◦. Details of the hydrogen bonds are
listed in Table 2. The coordination sphere of the cerium
atom can be described as distorted square antipris-
matic or bisphenoidal. The distance of the ammonia
molecule of solvation to the next nearest fluorine atom
Results and Discussion
Cerium(IV) fluoride dissolves sparingly in liquid
ammonia and forms the crystalline compound [CeF4-
c
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