1
912
Can. J. Chem. Vol. 76, 1998
employed in the analysis of the products of the ground state
solvolysis of these esters.
Identification of transients as benzylic carbocations
While there is no spectrum of an authentic cation available
for comparison, there is good evidence that the transients
observed with the three esters 7–9 are cations forming by
photoheterolytic cleavage of the α-carbon–oxygen bond.
Firstly, the stable products of irradiation are those expected
of a photosolvolysis. In the case of the thioamides 8 and 9 in
fact, there is a very efficient conversion to exactly the same
products obtained in the ground state solvolysis reaction.
Secondly, the transients are quenched by azide ion, a typical
carbocation trap. More importantly, the absolute rate con-
The final products of the irradiation were examined in
0% aqueous acetonitrile. These experiments were carried
4
out by preparing a solution of the precursor benzoate of con-
centration ~100 µM, which was then split in two. One half
was irradiated at 254 nm, while the other was kept in the
dark under conditions sufficient for complete ground state
solvolysis. The HPLC chromatograms of the two were then
compared, along with the chromatograms of the authentic
products of the ground state hydrolysis.
With 8, which undergoes a relatively rapid ground state
solvolysis, the solvent was cooled to 0°C before addition of
the substrate. After substrate addition, half was irradiated at
this temperature for 30 s, a time sufficient to remove 95% of
the precursor. The other half was warmed to room tempera-
ture and allowed to stand for a total time of 1 h. (The half-
life at 20°C is 4 min.) The products observed in both the ex-
cited state and ground state reactions were the alcohol 10
and pentafluorobenzoic acid (eq. [1]). Based on the relative
areas of the peaks (with a small correction for remaining
precursor), the yield of the the alcohol in the irradiated solu-
tion was 102% of that in ground state. Thus, within experi-
mental error, there was quantitative formation of the same
product of the ground state solvolysis.
stants kaz and k obtained by flash photolysis give selec-
s
tivities k :k that are essentially the same as those obtained
az
s
in the ground state solvolysis (7). This comparison was
made in 50:50 methanol:water and is shown in Table 1. In
the case of the cations 4 and 6, the flash photolysis ratio is
slightly larger but the difference is not outside experimental
error. With 2, the flash photolysis ratio is about two thirds of
that obtained in the competition experiment. The latter was,
however, obtained with azide ion concentrations in the range
0.5–1.0 mM, where >95% of the products arise from azide
trapping (7). This means that the amount of alcohol product
being measured is quite small, creating some uncertainty in
the final ratio.
The same conclusion was reached with 9. Again, 30 s ir-
radiation was sufficient to photolyze 95% of the precursor.
Four hours at 50°C was required for the ground state reac-
tion. The observed products from both were the alkene 12
and 4-methoxybenzoic acid (eq. [2]). The yield of alkene in
the irradiated solution was 97% of that of the solvolyzed
one.
With 9, the situation was more complicated. The pho-
tolysis was considerably less efficient, 3 min of irradiation
for example only reacting 45% of the starting material. A
consequence was that the products were not stable, unlike
the situation with the two thioamides, but underwent further
photochemistry. The solvolysis reaction required overnight
at 50°C for completion, and gave the expected alcohol 11
and pentafluorobenzoic acid (eq. [1]). These were also the
major products in the irradiated solution, but their yields ex-
pressed as a percentage of reacted 7 decreased with
increased irradiation time. Based on a three-point extrapola-
tion to zero irradiation, the yield of alcohol is 60–70%. The
HPLC chromatogram of the irradiated solution did have other
peaks, but these were not identified.
Rate constants for addition and elimination in cation 4
The reaction of the cation 4 gives only alkene product in
50:50 methanol:water (7). Thus the decay of this ion ob-
served in the flash photolysis experiments represents the re-
–
1
action with solvent acting as a base, and the k of 210 s is
s
equal to k (B) of eq. [3]. There is less than 1% of the ether
s
and alcohol products that would arise form nucleophilic ad-
–
1
dition of solvent. Thus k (Nu) < 2 s .
s
With azide ion, both elimination and addition occur. The
azide-catalyzed elimination is seen in the observation that
the alkene:RN ratio does not approach zero at high concen-
3
trations of azide, but plateaus, in fact, with a greater amount
of alkene (7). The limiting [alkene]:[RN ] is 1.69; this is
3
equal to the ratio of rate constants for azide acting as a base
and a nucleophile, k (B):k (Nu). The quenching that is ob-
az
az
served with azide ion in the flash photolysis studies repre-
sents the sum of these two processes, i.e., k (flash
az
photolysis) = k (B) + k (Nu). Since the ratio is known from
az
az
the product analysis, the absolute values of the two can be
4
–1 –1
calculated. Thus k (B) = 3.1 × 10 M
s
and k (Nu) =
az
az
©
1998 NRC Canada