
Inorganic Chemistry p. 2200 - 2203 (1968)
Update date:2022-08-18
Topics:
Prakash, Hari
Sisler, Harry H.
It has been shown that S4N3Cl gives a complex series of reactions in which [(C6H5)3P=NP(C6H5) 3]Cl (I), [(C6H5)3PNH2]Cl (II), and [{(C6H5)3PN}3S]Cl3 (III) are produced. Compound III reacts with two molecules of triphenylphosphine giving [{(C6H5)3PN}3S]Cl 3·2P(C6H5)3 (IV), which crystallizes out of acetone with 2 moles of acetone. N-Chlorotriphenylphosphinimine is suggested as a probable intermediate in these reactions.
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