T. Schmidt et al. / Journal of Organometallic Chemistry 696 (2011) 1760e1767
1767
[8] Since the substrate in the described Rh(III) alkyl complex contains a CH3 group
instead of the former vinylidenic CH2 group we use methyl succinate instead of
itaconate. A reasonable mechanism for the formation of this complex is
proposed in Ref. [3].
[9] (a) A. Salzer, Laboratory Techniques of Organometallic Chemistry (Chapter 2).
in: W.A. Herrmann (Ed.), Synthetic Methods of Organometallic and Inorganic
Chemistry, S. 8-28. Georg Thieme Verlag, Stuttgart, 1996;
Appendix A. Supplementary information
Supplementary data related to this article can be found online at
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[19] Upon formation of [Rh(DIPAMP)(methyl succinate) from itaconic acid and [Rh
(DIPAMP)(MeOH)2]BF4, 1 equivalent HBF4 is released (for details refer to
Ref. [3]). Because HBF4 is a strong acid and NEt3 is a strong base, we assume
that an equimolar solution of the two species should be neutral.
[20] The correlation was carried out via 1He13C measurements.
[21] The X-ray analysis of the complex isolated from CD3OD shows that it is the
same catalyst-substrate complex for which the X-ray structure had been
previously reported in Ref. [3]. Unfortunately, it was impossible to conclude
from the data whether an H or D atom had been transferred to the vinylidenic
CH2 group.
[6] T. Schmidt, Z. Dai, H.-J. Drexler, W. Baumann, C. Jäger, D. Pfeifer, D. Heller,
Chem. Eur. J. 14 (2008) 4469e4471.
[7] The X-ray structure of the complex surprisingly revealed that the substrate is
not coordinated via the CeC double bond and one carboxylate oxygen, but
instead via the two carboxylate oxygens and the quaternary carbon [C(2)]
atom. Formally the acidic functions of the substrate had been completely
deprotonated and the methylene group had been already converted into
a methyl group via H-transfer. The tetrafluoroborate anion was no longer
present in the crystal as the counterion. Thus, the complex represents
a neutral Rh(III) alkyl complex, compare Reference [3].