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than optimal as a contrast agent for in vivo EPR imaging. We
therefore sought alternative nitroxides that might exhibit narrow
EPR spectral lines. We decided to investigate the synthesis of
more water-soluble analogs of the reported pyrroloxyls4 with
the expectation that they would also exhibit narrow linewidths.
Results and discussion
Scheme 3. Reagents and conditions: (a) Bn–Br, K2CO3, DMSO (70% yield); (b)
HCON(CH3)C6H5/POCl3 (47% yield). Bn = benzyl.
Based on our earlier publication,6 it is clear that all positions on
the pyrrole ring must be substituted prior to the one-electron
oxidation of NꢁOH to NꢁO. We considered that preparation of
di-ester 8, followed by cyclization with hydroxylamine would
afford the desired pyrrole 9 (Scheme 2). A careful review of the lit-
erature5 revealed that 9 was indeed accordingly obtained, but only
in about 5% yield. In our hands, however, attempts to prepare 9 in
an identical fashion were unsuccessful.
An alternative approach was sought. We reasoned that since 4
can be readily prepared in reasonable yield,4,6 initial protection
of the NꢁOH followed by the Vilsmeier–Haack reaction might
result in the corresponding formylpyrrole 11. Oxidation of 11, fol-
lowed by removal of the protective group, should lead to 9. How-
ever, after O-benzylation of 4 to yield 10, classic Vilsmeier–Haack
reaction conditions7 did not result in formylation (only 10 was
recovered). By optimizing reaction conditions—1 equiv of 10 in
5 equiv of N-methyl-N-phenylformamide/POCl3 (solvent-free),
50 °C, 3 h, followed by hydrolysis with aqueous sodium
acetate—we obtained 11 in acceptable yield (Scheme 3).
Scheme 4. Reagents and conditions: (a) Oxone/EtOH (48% yield). Bn = benzyl.
While there are various methods for oxidizing aldehydes to
acids and esters, the recent procedure of Travis, et al.,8 wherein
OxoneÒ was used to convert aryl aldehydes to the corresponding
ethyl esters, seemed an attractive approach to pyrrole 12. One
potential problem was that electron-rich molecules, such as
4-hydroxybenzaldehyde, can also undergo the Baeyer–Villiger
reaction, resulting in a formate ester, which upon hydrolysis leads
to the corresponding phenol.8 Because pyrrole 11 is not electron-
rich, we were optimistic that the mild experimental conditions
described in Travis, et al.8 might favor oxidation to the desired
ester and not a Baeyer–Villiger rearrangement.
When 11 and OxoneÒ (2:1 molar ratio of KHSO5 to substrate)
were stirred in absolute ethanol at room temperature for 16 h,
no reaction occurred. When the ratio of KHSO5 to 11 was increased
to 6, and the reaction was vigorously stirred at room temperature
for 3 days, TLC analysis indicated the formation of
a new
compound. The 1H NMR spectrum of the isolated product showed
multiple resonances inconsistent with the highly symmetrical
structure of 12. The X-ray crystallographic structure9 of the iso-
lated product revealed a rearrangement of 11 by OxoneÒ, resulting
in 13 rather than the predicted pyrrole 12 (Scheme 4). The
presence of a chiral center in 13 implies the generation of stereo-
isomers. Indeed, 13 crystallizes as a racemate, with an asymmetric
unit comprising a pair of enantiomers (Fig. 1).
We speculated that 11 could have undergone a Baeyer–Villiger-
type oxidation mediated by OxoneÒ, with subsequent rearrange-
ment to 13. To gain further insight into the mechanism underlying
the formation of 13, we changed experimental conditions to avoid
using a protic solvent that could act as a nucleophile: reaction with
Figure 1. Enantiomers of 13 constituting the asymmetric unit in the X-ray
crystallographic structure.9
3
molar equivalents of OxoneÒ in DMF for 16 h at room
temperature transformed 11 into a new product, 16. The 1H NMR
spectrum of 16 suggested the presence of a formate ester. The
structure of 16 was determined by X-ray crystallography
(Fig. 2),10 and is seen to be the formate ester expected from Bae-
yer–Villiger oxidation of 11 (Scheme 5).
Oxone is an acidic triple salt comprising potassium peroxy-
monosulfate, potassium hydrogen sulfate, and potassium sulfate
(2KHSO5ꢂKHSO4ꢂK2SO4). Therefore, if formate ester 16 did form in
the ethanolic Oxone reaction, acid-catalyzed transesterification
Scheme 2. Reagents and conditions: (a) Na/Et2O, (b) NH2OH.