A. Nomland, I. D. Hills / Tetrahedron Letters 49 (2008) 5511–5514
5513
O
O
10% TMG
NO2
2.0 M toluene X
H
Me
Me
110 ºC
X
X
X = C or N
No ketone formation.
O
O
10% TMG
N
N
H
Me
2.0 M toluene
110 ºC
15% isolated yield
Scheme 3. Structural analogues of 2-quinolinecarboxaldehyde do not lead to a ketone product (top); 2-pyridinecarboxaldehyde does furnish a ketone product (bottom).
Loss of
H2O
Loss of
HNO2
O
H
HO
H
X
NO2
NO2
N
Me
H
H
H
X = N
X = C
Scheme 4. Substrate-dependent elimination leading to different types of products.
O
O
HO
Loss of
HBr
H
Br
NO2
10% TMG
N
N
NO2
Br
N
H
H
No Loss
of HNO2
NO2
2.0 M toluene
110 °C
40% NMR yield
Scheme 5. Use of bromonitromethane to access a nitromethyl ketone.
any analytical evidence (LC–MS or NMR) of methyl ketone forma-
tion (Scheme 3, top); however, when 2-pyridinecarboxaldehyde
was employed, 2-acetylpyridine was isolated, albeit in low yield
(Scheme 3, bottom).9
Thus after the putative formation of a mesylate leaving group, 2-ni-
tro-vinylquinoline can be smoothly generated in 60% yield
(Scheme 6).
In summary we have shown that 2-quinolinecarboxaldehyde
can smoothly undergo the standard Henry reaction with a variety
of nitroalkanes. However, instead of the typical loss of water to
yield nitroalkenes, an apparent loss of nitrous acid is observed, fur-
nishing ketone products. We do not believe that HNO2 elimination
is a particularly facile process and it is clearly not the preferred
path when a substrate capable of eliminating HBr is employed.
While the standard elimination of water is not readily observed,
the addition of MsCl allows for the formation of the expected
2-nitro-vinylquinoline. We continue to study the mechanistic
aspects of this unique transformation as well as try to extend this
reaction to an aldehyde substrate other than 2-quiniolinecarbox-
aldehyde. We hope to report the results of these investigations in
due course.
With these observations in hand, it is apparent that the sub-
strate-dependent formation of either nitroalkenes or ketones from
a b-nitro alcohol can be explained by two different elimination
reactions (Scheme 4). Thus the standard dehydration reaction
yields the expected nitroalkene; however, the formal elimination
of nitrous acid ultimately furnishes the ketone. While we do not
fully understand the role of the nitrogen atom in the 2-quinoline
scaffold, clearly it facilitates the loss of HNO2 over that of H2O.10
We were intrigued by this apparent reversal in elimination
propensity between water and nitrous acid; however, we do not
believe that the presence of the quinoline nitrogen confers
excellent elimination ability to HNO2. When we examined
bromonitromethane under our reaction conditions, we observed
the formation of a nitromethyl ketone and were unable to acquire
any evidence of HNO2 elimination (Scheme 5). We believe this
compound to be derived from the elimination of HBr from the
standard b-nitro alcohol intermediate. Finally, we have been able
to direct the b-nitro alcohol intermediate derived from 2-quinoline-
carboxaldehyde and nitromethane toward the nitroalkene product
by inducing the formal elimination of water by addition of MsCl.2c,d
Supplementary data
Supplementary data associated with this article can be found, in
References and notes
1. (a) Barrett, A. G. M.; Graboski, G. G. Chem. Rev. 1986, 86, 751–762; (b) Luzzio, F.
A. Tetrahedron 2001, 57, 915–945; (c) Palomo, C.; Oiarbide, M.; Mielgo, A.
Angew. Chem., Int. Ed. 2004, 43, 5442–5444; (d) Boruwa, J.; Gogoi, N.; Saikia, P.
P.; Barua, N. C. Tetrahedron: Asymmetry 2007, 17, 3315–3326; (e) Palomo, C.;
Oiarbide, M.; Laso, A. Eur. J. Org. Chem. 2007, 2561–2574.
2. (a) MacNevi, C. J.; Moore, R. L.; Liotta, D. C. J. Org. Chem. 2008, 73, 1264–1269;
(b) Calmes, M.; Escale, F.; Didierjean, C.; Cazals, G.; Martines, J. Tetrahedron:
Asymmetry 2007, 18, 2491–2496; (c) Franck, X.; Fournet, A.; Prina, E.;
O
N
NO2
1. 10% TMG
NO2
Me
N
H
2. MsCl
toluene
60% isolated yield
Scheme 6. Reaction with MsCl leads to nitroalkene formation.