H. Kunkely, A. Vogler / Inorganic Chemistry Communications 9 (2006) 248–250
249
2
-
PdIV
L
Pd
L
L
L
L
L
2a1
b1u
2e
LMCT
ꢀ5
Fig. 1. Spectral changes during the photolysis of 6.93 · 10
M
[
(Ph )PdCl in CH CN at room temperature after 0 s (a), 5, 10, 20
4
C
4
2
]
2
3
eg
and 80 s (b) irradiation times with kirr > 340 nm (Osram HBO 200 W/2
lamp; Schott cut off WG 360), 1 cm cell.
[
(C Ph )PdCl ] in CH CN are not luminescent, the
4 4 2 2 3
1
a1
irradiation leads to the appearance of an emission at
kmax = 389 nm which shows an excitation spectrum with
kmax = 275, 315, 340 and 360 nm. This luminescence is
apparently caused by octaphenylcyclooctatetraene [7]. In
agreement with these observations the photolysis proceeds
according to a rather simple equation:
1e
a2u
½
ðC
!
4
Ph
4
ÞPdCl
2
ꢁ2 þ 4CH
3
CN
2PdðCH
3
CNÞ Cl
2
þ C
8
Ph
8
ð1Þ
2
IV
4 4 3
Fig. 2. MO diagram of (C H )Pd L complexes, adapted from Ref. [13].
The progress of the photolysis was monitored by mea-
2
ꢀ
suring the decrease of the optical density at 387 nm. The
quantum yield for the disappearance of [(C Ph )PdCl ]
2 2
4
4
ligand (Fig. 2). Although C H is an aromatic 6p-elec-
tron system it is not stable because the degenerate
4
4
was / = 0.08 at kirr = 436 nm.
The dimeric compound [(C Ph )PdCl ] consists of two
HOMO e is nonbonding and located at very high ener-
g
2ꢀ
gies. However, in complexes, C H is stabilized because
4
4
4
2 2
4
monomeric (C Ph )PdCl fragments. To a first approxima-
the e orbitals are lowered by bonding interaction with
4
4
3
g
tion the electronic features can be explained by the proper-
ties of the mononuclear components. The assignment of
two negative charges to the C Ph ligand leads to the con-
the metal [9–13]. According to the high oxidation state
of Pd(IV) the d orbitals are situated at relatively low
energies. In the complex fragment the frontier orbitals
4
4
2ꢀ
clusion that palladium exists in the oxidation state IV. It
4
4
g 3
are derived from the C H e and the PdL 2e metal d
6
follows that the metal has a d electron configuration which
orbitals. The HOMO and the LUMO are strongly delo-
2
4
ꢀ
IV
requires an octahedral coordination. Indeed, the
calized between C H
and Pd . However, in the
4
(
C Ph )PdCl fragment can be viewed as an octahedral
HOMO which is C H –Pd bonding, the ligand character
4 4
prevails while the LUMO which is C H –Pd antibonding
4 4
4
4
3
2ꢀ
complex since the C Ph ligand provides three p-electron
4
4
pairs for the occupation of three bonding sites at
palladium.
is dominated by the metal d-orbitals. In summary, the
electronic structure of C H PdCl can be easily described
4
4
3
IV
What are the low-energy transitions of (C Ph )Pd Cl3?
on the basis of the occupied MOs (Fig. 2). While the
degenerate HOMO and the lowest-energy MO (a2u of
C H ) represent the three p-electron pairs of the ligand
4
4
6
Palladium(IV) with a d configuration has available LF
states but at very high energies [8]. Moreover, the LF
absorptions (t2g ! e in O symmetry) are generally quite
4
4
2
ꢀ
g
h
4
C H , the three other occupied MOs (1a and 1e of
4
1
2
ꢀ
IV
weak. In contrast, a C Ph ! Pd LMCT transition is
PdL ) correspond to the t d-orbitals of an octahedral
3 2g
4
4
6
expected to occur at rather low energies since Pd(IV) is
d complex. The HOMO–LUMO transition can be for-
mally viewed as LMCT transition (Fig. 2) but in reality
the participating MOs are strongly mixed and the extent
of charge separation may be rather small. Irrespective of
2
ꢀ
strongly oxidizing [8] and C Ph4 is certainly a strong
4
reductant. Consistent with this assumption we assign the
longest-wavelength absorption at 530 nm to the
2
ꢀ
IV
2ꢀ
IV
C
4
Ph4 ! Pd LMCT transition of the complex.
IV
these details the C H ! Pd LMCT excitation is not
ꢀ
IV
4
4
4
2
Let us now have a closer look at the electronic struc-
ture of (C H )Pd L complexes with L = any simple
only associated with a charge shift from C H to Pd
4
but also with a strong destabilization of the C H –Pd
4 4
4
4
3