
Journal of Organometallic Chemistry p. 141 - 154 (1996)
Update date:2022-08-17
Topics:
Marchetti, Fabio
Pettinari, Claudio
Cingolani, Augusto
Lobbia, Giancarlo Gioia
Cassetta, Alberto
Barba, Luisa
New triorganotin(IV) derivatives [(Q)SnR3 · x(H2O)] (x = 0, R = Ph; x = 1, R = Me and nBu) (in general QH = 1-R′-3-methyl-4-R″ (C=O)-pyrazol-5-one; in detail Q′H: R′ = C6H5, R″ = C6H5; QAH: R′ = C6H5, R″ = p-CH3O-C6H4; QNH: R′ = C6H5, R″ = p-NO2-C6H4; QBrH: R′ = C6H5, R″ = p-Br-C6H4; Q″ H: R′ = C6H5, R″ = CH3; QClH: R′ = C6H5, R″ = CCl3; QFH: R′ = C6H5, R″ = CF3; QMH: R′ = CH3, R″ = C6H5; QDH: R′ = CH3, R″ = CH3) have been synthesized and characterized by analysis and spectral (IR and 1H, 13C and 119Sn NMR) data. The (Q)SnPh3 derivatives are five-coordinated in the solid state, with a likely skewed cis-trigonal bipyramidal (cis-TBP) geometry around the tin center and the ligand (Q)- acting in the bidentate form. In [(Q)SnR3 · (H2O)] derivatives (R = nBu or Me) a coordination site is occupied by water, with the ligand (Q)- coordinating in a monodentate fashion. The crystal structure of [(QA)SnMe3 · (H2O)] has been determined: the tin atom is found in a distorted TBP environment, with the methyls in the equatorial positions. Two of the Sn-C bond lengths are normal (2.11(1) and 2.08(2) A) whereas the third is longer (2.18(2) A); the ligand binds the metal atom through one carbonyl oxygen in the apical position (Sn-O = 2.10(1) A). The bond length between H2O and Sn is longer (2.41(2) A), and the O-Sn-O angle is 174.9(5)°. H atoms of water are involved in an intermolecular H-bond network with uncoordinated carbonyl and the pyridinic N atom of the ligand. In chloroform solution the [(Q)SnR3 · (H2O)] derivatives (R = Me or nBu) lost the molecule of water and adopt a tetrahedral arrangement. They also give rise to a slow disproportionation, yielding SnR4 and [(Q)2SnR2] derivatives.
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