
Polyhedron p. 2665 - 2671 (1999)
Update date:2022-08-04
Topics:
Burrows, Andrew D.
Coleman, Marc D.
Mahon, Mary F.
The reaction of [PtCl2(dppe)] [dppe=1,2-bis(diphenylphosphino)ethane] with two equivalents of the thioureas NHRC(S)NHR (R=H, Me, Et) in the presence of NH4PF6 led to substitution of both chlorides and formation of the complexes [Pt(dppe){SC(NHR)2}2](PF6)2 (1a, R=H; 1b, R=Me; 1c, R=Et). In contrast, the reaction of [PtCl2(dppe)] with one equivalent of the potentially bidentate thiosemicarbazides NHRC(S)NHNR′2 (R=Me, R′=H; R=Et, R′=H; R=Ph, R′=H; R=Me, R′=Me) in the presence of NH4PF6 led to substitution of only one chloride and formation of the complexes [PtCl(dppe){SC(NHR)NHNR2′-S}](PF6) (2a, R=Me, R′=H; 2b, R=Et, R′=H; 2c, R=Ph, R′=H; 2d, R=Me, R′=Me). An X-ray analysis of complex 2d revealed that an intramolecular N-HCl hydrogen bond [N(2)Cl(1)=3.29(2) A] helps to stabilise the monodentate co-ordination mode. The chloride ligand can be abstracted from complex 2d by treatment with TlPF6, and this reaction led to formation of [Pt(dppe){SC(NHMe)NHNMe2-S,N}](PF6)2 3d. Reaction of [PtCl2(dppe)] with unsubstituted thiosemicarbazide NH2C(S)NHNH2 in the presence of NH4PF6 resulted in a mixture of products containing mono- and bidentate co-ordinated ligands, [PtCl(dppe){SC(NH2)NHNH2-S}](PF6) 2e and [Pt(dppe){SC(NH2)NHNH2-S,N}](PF6)2 3e. [PtCl2(dppe)] also reacts with two equivalents of NHMeC(S)NHNMe2 in the presence of NH4PF6 to yield [Pt(dppe){SC(NHMe)NHNMe2-S}2](PF6)2 1d, in which the thiosemicarbazide is acting as an S-donor, directly analogous to the thiourea ligands in complexes 1a-c. Elsevier Science Ltd.
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