
Journal of the Chemical Society - Faraday Transactions p. 3641 - 3645 (1997)
Update date:2022-08-11
Topics:
Barlow, Susan
Buxton, George V.
Murray, Samantha A.
Salmon, G. Arthur
At pH 4.0, the radical .CH(OH)SO3- formed by reaction of .OH with hydroxymethanesulfonate (HMS) reacts rapidly with oxygen to form the peroxyl radical, .OOCH(OH)SO3-, with k4 = (2.6 ± 0.3) × 109 dm3 mol-1 s-1. This radical decays by a first-order process with k = 2.4 × 104 s-1 and Ea = (29 ± 1.2) kJ mol-1. The decay is by a split pathway, reactions (6) and (7), with k6 = 1.7 × 104 s-1 and k7 = 7.0 × 103 s-1. Reaction (6) involves direct elimination of HO2.. Reaction (7) initially forms the formylperoxyl radical, but this is hydrolysed, reaction (8), to formic acid and HO2. with k8 = 2.46 × 103 s-1. .CH(OH)SO3- + O2 → .OOCH(OH)SO3- (4) .OOCH(OH)SO3- → HO2. + CHOSO3- (6) .OOCH(OH)SO3- → .OOCHO + HSO3- (7) .OOCHO + H2O → .OOCH(OH)2 → HCOOH + HO2. (8) The yield of formate is compatible with this mechanism if it is assumed that the product of reaction (6), i.e. CHOSO3-, can also yield formic acid. Yields of SO42- have been determined and their origin is considered. At pH 7.0, the radical .CH(O-)SO3- reacts with oxygen to yield O2.- with k11 = (1.6 ± 0.1) × 109 dm3 mol-1 s-1. .CH(O-)SO3- + O2 → CHOSO3- + O2.- (11).
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