144 Bull. Chem. Soc. Jpn., 77, No. 1 (2004)
Ph Ligand Transfer of Pd and Pt
Reaction of [PtPh2(dppe)] with [PdCl2(cod)]. A solution of
[PtPh2(dppe)] (74.8 mg, 0.10 mmol) and [PdCl2(cod)] (57.1 mg,
0.20 mmol) in CH2Cl2 (5.0 cm3) was stirred for 20 h at room tem-
perature. After removal of a small amount of black solid, the sol-
vent was evaporated to give a brown solid. The 1H NMR spectrum
in CDCl3, using 1,1,1,2-tetracholoroethane as an internal standard,
revealed formation of 1 (76%) and [PdCl2(cod)] (11%). The
31P{1H} NMR spectrum showed the presence of [PtCl2(dppe)]
and the absence of [PtPh2(dppe)] and [PtCl(Ph)(dppe)]. Overlap
of the 1H NMR peak of [PtCl2(dppe)] with other products prevent-
ed determination of its yield.
in the reaction mixture.
Reaction of [PtPh2(cod)] with [PdCl(ꢀ3-C3H5)]2. A solution
of [PtPh2(cod)] (46.0 mg, 0.10 mmol) and [PdCl(ꢁ3-C3H5)]2 (36.6
mg, 0.10 mmol) in acetone/CH2Cl2 (1:1 v/v, 10 cm3) was stirred
for 2 days at room temperature. Evaporation of the solvent gave a
gray solid, which was analyzed by 1H NMR in CDCl3 using
1,1,1,2-tetracholoroethane as an internal standard. The products
contained biphenyl (0.023 mmol, 5%), [PtPh2(cod)] (0.084 mmol,
84%), [PtCl(Ph)(cod)] (0.012 mmol, 12%), and [PdCl(ꢁ3-C3H5)]2
(0.094 mmol, 94%). The products of the reaction for 12 days con-
tained biphenyl (0.013 mmol, 26%), [PtPh2(cod)] (0.049 mmol,
49%), [PtCl(Ph)(cod)] (0.040 mmol, 40%), and [PdCl(ꢁ3-C3H5)]2
(0.082 mmol, 82%).
Reaction of [PtCl(Ph)(cod)] with [PdCl2(cod)]. A solution of
[PtCl(Ph)(cod)] (41.6 mg, 0.10 mmol) and [PdCl2(cod)] (28.6 mg,
0.10 mmol) in CH2Cl2 (5.0 cm3) was stirred for 14 h at room tem-
perature. Evaporation of the solvent gave a gray powder, which
This work was supported by a Grant-in-Aid for Scientific Re-
search from the Ministry of Education, Culture, Sports, Science
and Technology.
1
was analyzed by H NMR spectrum in CDCl3 using 1,1,1,2-tetra-
choloroethane as an internal standard. Both the products, 1 and
[PtCl2(cod)], were formed quantitatively.
Reaction of [PtPh2(bpy)] with [PdCl2(cod)]. A solution of
[PtPh2(bpy)] (50.5 mg, 0.10 mmol) and [PdCl2(cod)] (57.1 mg,
0.20 mmol) in CH2Cl2 (5.0 cm3) was stirred for 20 h at room tem-
perature. Although the palladium complex was dissolved, a part of
[PtPh2(bpy)] remained undissolved. After the evaporation, the
products were analyzed by 1H NMR spectrum in CDCl3 using
1,1,1,2-tetracholoroethane as an internal standard. Complex 1
was formed in 6% yield.
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Reaction of [PtPh2(cod)] with [Pd(acetone)2(cod)]2þ(BF4ꢀ)2.
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