Organic Letters
Letter
neously released, which is necessary to trigger the rearrange-
ment. To gain insight into the mechanism of the rearrange-
ment, the quantum chemical calculations of the transformation
of azirine 1a to tetrazole 2a were performed at the B3LYP-D3/
6-311+G(d,p) level of theory with the SMD model for
methanol (Figure 2; for details of the calculations, see the
Scheme 2. Synthesis and Rearrangement of the Labelled
Azirine 1a
a
According to the calculations, methanol cannot extrude HN3
directly from azirine 1a to give azirine 3a, while MeO− reacts
without an energy barrier with azirine 1a to give azirine 3a and
the azide anion. The formation of MeO− can be the result of
an equilibrium reaction between methanol and a base, and
since the azirine is initially the only base in the reaction
mixture and it is weak, the concentration of the methoxide
must be very low. Neither azirine 1a nor azirine 3a is capable
of adding a nucleophilic azide anion to the CN double bond,
while the corresponding protonated azirines easily react with
the azide anion. Thus, complexes A and B of azirines 1a and 3a
with HN3 give azidoazirines C and D through the energy
barriers, which are surmountable at rt. The route from
diazidoaziridine C to tetrazole 2a (Figure 2, blue route)
involves conformational transformations C → E → F, the
aziridine ring opening in F with formation of the stabilized W-
azomethine ylide G, followed by its isomerization to S-
azomethine ylide H and extrusion of HN3 from the latter to
give ketene I. The reaction of ketene I with MeOH affords
azidoimine J which transforms to the conformation K, suitable
for the cyclization of azidoimine K to tetrazole 2a. According
to the calculations, all the mentioned transformations proceed
through energy barriers surmountable at rt. Similarly,
azidoaziridine D can give tetrazole 2a via the transformations
D → L → M → N → O → I → J → K (Figure 2, yellow
route), but this route passes through TS12 with a higher
relative Gibbs free energy (24.4 kcal/mol) than TS5 (19.7
kcal/mol), so these routes do not compete as long as azirine 1a
is present in the reaction mixture.
a
Reagents: (a) HO15NH2·HCl; (b) POCl3, NEt3; (c) (1) FeCl2, (2)
NaN3.
1,5-diphenyl-1H-tetrazole,14 the 15N NMR signals of 2b were
assigned as follows: 222.0 (N1), 328.7 (N4), 372.7 (N2), and
392.2 ppm (N3). In the 15N NMR spectrum of 2b(15N), the
most intensive peak is at 221.9 ppm, so we can conclude that
azirine nitrogen of 1 appears as the N1 in the tetrazole 2b. The
structure of tetrazole 2b was also confirmed by single-crystal X-
ray diffraction analysis.
To obtain information on the rates of consumption of the
starting azidocarbonylazirine and the formation of the target
tetrazole, as well as a possible intermediate and/or byproducts
(one of which is azirine 3), kinetic 19F NMR experiments were
carried out using azirine 1c as starting material and 4-
(trifluoromethyl)benzonitrile, which is inert under the reaction
conditions, as an internal standard (Figure 1). According to the
According to the presented mechanism (Figure 2), acid−
base relationships in the reaction mixture should have an
influence on the rearrangement rate. To check this, an
additional experiment with fluorinated azirine 1c and
CD3OD in the presence of 20 mol % Et3N, using 19F NMR,
was performed (Figure 3).
According to the results obtained, the addition of Et3N
significantly accelerates the reaction. Thus, the concentration
of tetrazole 2c in the presence of Et3N reaches a maximum
already in 3 h (Figure 2), whereas, without a base, it reaches a
maximum in 6 h (Figure 3). The effect can be attributed to an
increase in the concentration of MeO−, which promotes the
−
release of N3 . Several other bases (DMAP, TMEDA) also
accelerate the reaction, in contrast to pyridine, which has no
effect. The base and their amount have practically no influence
on the yield of the target tetrazole 2a, but the amount of the
byproduct, azirine 3a, is affected (see Table S1 in the
Figure 1. Time dependence of the relative content of 1c, 2c(D), and
3c(D) in the reaction mixture based on the integral intensities of 19F
NMR signals normalized to the internal standard.
According to the presented mechanism (Figure 2), the
addition of HN3 should catalyze the rearrangement. To check
this, an additional experiment with fluorinated azirine 1c and
CD3OD in the presence of 20 mol % N3H, using 19F NMR,
was performed (Figure 4). Indeed, in full agreement with the
proposed mechanism the N3H additive catalyzes the reaction.
Moreover, this additive increases the tetrazole yield and makes
the spectral overall yield tetrazole 2c(D) + 3c(D) practically
quantitative, probably due to the fact that the additive
data obtained, the concentration of methoxycarbonylazirine
3c(D) in the reaction mixture increases faster during the first 2
h than the concentration of tetrazole 2c(D), and then the
concentration of tetrazole 2c(D) continues to increase, while
the concentration of methoxycarbonylazirine 3c(D) remains
almost constant. This may mean that either azirine 3c(D) is an
intermediate product on the way to tetrazole 2c(D) or, when it
−
is formed from azidocarbonylazirine 1, N3 /HN3 is simulta-
6363
Org. Lett. 2021, 23, 6362−6366